How i send email without authentication using java

Question

I would like to send email without authentication using java. Can someone help me?

With authentication, I do it as follows:

    public void sendEmail() throws EmailException{
    SimpleEmail email = new SimpleEmail();
    email.setHostName("smtp.gmail.com");
    email.setSmtpPort(465);
    email.addTo("[email protected]", "XXXX");
    email.setFrom("[email protected]","XXXXX");
    email.setSubject("testando . . .");
    email.setMsg("testando 1");
    email.setSSL(true);
    email.setAuthentication("[email protected]", "XXXXX");
    email.send();
}

I forgot to say that i do not have a provider. i need an provider finally, i have emailFrom Subject and Message, and need send this email how?

This has nothing to do with Java. You can send email without authenticating only if the mail server allows it, in which case you would omit the setAuthentication() call. If the SMTP server requires authentication you must provide it. If you are testing you can use a mock SMTP server, or set up your own real SMTP server and configure it without authentication. — Jim Garrison
– Jim Garrison, Commented Apr 3, 2014 at 15:29

Martin Pfeffer · Accepted Answer · 2019-11-12 12:14:15Z

6

If it is only for testing purposes, you may try Papercut. While it’s running, Papercut automatically picks up e-mail sent to the standard SMTP port (25) on any IP address. You just send mail from your application and switch to Papercut to review it.

Papercut @ github: https://github.com/ChangemakerStudios/Papercut/releases

import java.util.Date;
import java.util.Properties;

import javax.mail.Message.RecipientType;
import javax.mail.Session;
import javax.mail.Transport;
import javax.mail.internet.InternetAddress;
import javax.mail.internet.MimeMessage;

public class SendMail {

    public static void main(String[] args) throws Exception {
        Properties props = new Properties();
        props.put("mail.smtp.host", "127.0.0.1");
        props.put("mail.smtp.port", "25");
        props.put("mail.debug", "true");
        Session session = Session.getDefaultInstance(props);
        MimeMessage message = new MimeMessage(session);
        message.setFrom(new InternetAddress("[email protected]"));
        message.setRecipient(RecipientType.TO, new InternetAddress("[email protected]"));
        message.setSubject("Notification");
        message.setText("Successful!", "UTF-8"); // as "text/plain"
        message.setSentDate(new Date());
        Transport.send(message);
    }

}

edited Nov 12, 2019 at 12:14

Martin Pfeffer

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answered Apr 3, 2014 at 15:24

Paul Vargas

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2 Comments

sskumar86 Over a year ago

If I want to use sendgrid apikey ,how I should send it ?

Akito Over a year ago

The Github link is still working, but the website link to Papercut is down.

sarbjeet singh · Accepted Answer · 2020-02-13 07:14:09Z

3

import java.util.*;
import javax.mail.*;

public class SimpleEmail {

    public static void main(String[] args) {
        System.out.println("SimpleEmail Start");
        String smtpHostServer = "smtp.gmail.com";
        String toEmail = "[email protected]";
        Properties props = System.getProperties();
        props.put("mail.smtp.host", smtpHostServer);
        props.put("mail.smtp.starttls.enable", true);
        props.put("mail.smtp.port", "25");
        Session session = Session.getDefaultInstance(props);
        try {
            MimeMessage msg = new MimeMessage(session);
            msg.addHeader("Content-type", "text/HTML; charset=UTF-8");
            msg.addHeader("format", "flowed");
            msg.addHeader("Content-Transfer-Encoding", "8bit");
            msg.setFrom(new InternetAddress("[email protected]", "NoReply-JD"));
            msg.setReplyTo(InternetAddress.parse("[email protected]", false));
            msg.setSubject("SimpleEmail Testing Subject", "UTF-8");
            msg.setText("SimpleEmail Testing Body", "UTF-8");
            msg.setSentDate(new Date());
            msg.setRecipients(Message.RecipientType.TO, InternetAddress.parse(toEmail, false));
            System.out.println("Message is ready");
            Transport.send(msg);
            System.out.println("EMail Sent Successfully!!");
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

answered Feb 13, 2020 at 7:14

sarbjeet singh

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1 Comment

sarbjeet singh Over a year ago

Facing An Issue com.sun.mail.smtp.SMTPSendFailedException: 530-5.7.0 Authentication Required. Learn more at 530 5.7.0 support.google.com/mail/?p=WantAuthError o6sm1435614pgg.37 - gsmtp at com.sun.mail.smtp.SMTPTransport.issueSendCommand(SMTPTransport.java:2249) at com.sun.mail.smtp.SMTPTransport.mailFrom(SMTPTransport.java:1740) at com.sun.mail.smtp.SMTPTransport.sendMessage(SMTPTransport.java:1239) at javax.mail.Transport.send0(Transport.java:255) at javax.mail.Transport.send(Transport.java:124) at com.necti.smsemail.SimpleEmail.main(SimpleEmail.java:59)

Adriano · Accepted Answer · 2014-04-03 15:11:52Z

0

Try this example:

// File Name SendEmail.java

import java.util.*;
import javax.mail.*;
import javax.mail.internet.*;
import javax.activation.*;

public class SendEmail
{
   public static void main(String [] args)
   {    
      // Recipient's email ID needs to be mentioned.
      String to = "[email protected]";

      // Sender's email ID needs to be mentioned
      String from = "[email protected]";

      // Assuming you are sending email from localhost
      String host = "localhost";

      // Get system properties
      Properties properties = System.getProperties();

      // Setup mail server
      properties.setProperty("mail.smtp.host", host);

      // Get the default Session object.
      Session session = Session.getDefaultInstance(properties);

      try{
         // Create a default MimeMessage object.
         MimeMessage message = new MimeMessage(session);

         // Set From: header field of the header.
         message.setFrom(new InternetAddress(from));

         // Set To: header field of the header.
         message.addRecipient(Message.RecipientType.TO,
                                  new InternetAddress(to));

         // Set Subject: header field
         message.setSubject("This is the Subject Line!");

         // Now set the actual message
         message.setText("This is actual message");

         // Send message
         Transport.send(message);
         System.out.println("Sent message successfully....");
      }catch (MessagingException mex) {
         mex.printStackTrace();
      }
   }
}

Via: tutorialspoint

answered Apr 3, 2014 at 15:11

Adriano

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2 Comments

felipe muner Over a year ago

I forgot to say that i do not have a provider. i need an provider finally, i have emailFrom Subject and Message, and need send this email how?

Adriano Over a year ago

You saw the link at the end of the answer? I do not quite understand your doubts here in comment?

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