How to call a function with a parameter as string in php?

Question

I am looking for something similar to the solution here >> Call function from string stored in a variable, however with one difference :

I would like to pass a parameter as well.

For example :

   function foo($myvar) {

   }


   $function = 'foo';
   $values = Array('myvar'=>1, 'myvar2'=>2);

   if(function_exists($function)) {
      // call the function using $function, 
      // and pass the value $values -- aka   $function($values)

   }

Any workable solution would be greatly appreciated. Ideally, I would like to use it with classes as follows :

   class bar {

   function foo($myvar) {

   }

   }


   $function = 'foo';
   $values = Array('myvar'=>1, 'myvar2'=>2);

   if(function_exists($function)) {
      // call the function using $function, 
      // and pass the value $values -- aka   $bar::$function($values)

   }

I don't see where is the problem ? Can you give an example where it would cause a problem / — CMPS
– CMPS, Commented Apr 13, 2014 at 4:57
It's not a problem --- My question is how can i pass a variable to a function where the function name is stored in a variable. Calling the function directly is not the issue. If you look at the SO link i added, it gives an answer for how to call a function in a string, but not if i wish to pass a variable to that function as well. -- so it's only 50% of the solution i need — Kraang Prime
– Kraang Prime, Commented Apr 13, 2014 at 5:02

Community · Accepted Answer · 2023-11-17 20:33:26Z

3

You can call a function on an object passing params, using variables, as follows:

$myBar = new bar(); // usually class names have uppercase first letters though
$myClassname = 'bar';
call_user_func(array($myBar, $function), $values); // method on object
call_user_func(array($myClassname, $function), $values); // class (static) method
call_user_func($myClassname.'::'.$function); // PHP 5.2.3 and higher
// if you had another function $function2 whose args were a list of parameters instead of an array:
call_user_func($myBar, $function2, $param1, $param2, $param3);

More info and examples at https://www.php.net/call_user_func

edited Nov 17, 2023 at 20:33

CommunityBot

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answered Apr 13, 2014 at 5:03

RobP

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6 Comments

Kraang Prime Over a year ago

can the class itself be called this way as well ? for example, in your example, the class is known and is static --- but something like $foo = 'bar'; $mybar = new $foo; ? or more specifically calling it statically like $foo::$myfunction($params) so all parts can be dynamic

RobP Over a year ago

Yes. stackoverflow.com/questions/4578335/…

Kraang Prime Over a year ago

Awesome --- thank you :) -- lol... i have to wait to accept the answer XD

RobP Over a year ago

you're welcome! hope it helps. (ahh the things we'll do for an upvote or a green checkmark ;)

Kraang Prime Over a year ago

:) ... I have a follow up question coming ... hehe... slightly more complex, but on topic with this -- basically, I am writing an event class (so I can raiseevents from other functions/classes/etc). PHP doesn't seem to have any real event based system.

|

CMPS · Accepted Answer · 2014-04-13 05:09:10Z

1

Does this helps ?

function process_function($function_param){
 $function_param = explode("|",$function_param);
   if(function_exists($function_param[0])) {
      call_user_func_array($function_param[0],$function_param[1]);
   }
}

answered Apr 13, 2014 at 5:09

CMPS

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1 Comment

Kraang Prime Over a year ago

Also a good solution. Allows for passing of the function name and one param. RobP answered first and is a bit more thorough, however bump for decent solution anyway :) Thank you.

Suman Bogati · Accepted Answer · 2014-04-13 05:13:21Z

1

I think you are looking for method_exist() which would check if object has particular method.

Here is your solution.

class bar {
   function foo($myarr){
        foreach($myarr as $val){
            echo $val ."<br />" ;
            //prints 1 and 2
        }
   }
}

$myfunc = new bar(); //creating object 
$values = Array('myvar'=>1, 'myvar2'=>2);

//checking object has method foo
if(method_exists($myfunc, 'foo')) {
    $myfunc->foo($values);
}

answered Apr 13, 2014 at 5:13

Suman Bogati

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1 Comment

Kraang Prime Over a year ago

Thank you .... that is helpful as well. I wish we could just combine all 3 answers into a single solution. That doesn't really help with calling the function by string, but it does help with checking existence of function in a class.

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