Django-Rest-Framework AssertionError HTTPresponse Expected

Question

When i do the following command over Terminal using curl

curl -X POST http://myuser:[email protected]:8000/call/make-call/ -d "tutor=1&billed=1"

I get the following error

AssertionError at /call/make-call/ Expected a Response, HttpResponse or HttpStreamingResponse to be returned from the view, but received a <type 'NoneType'>

My views.py is

@api_view(['GET', 'POST'])
def startCall(request):

    if request.method == 'POST':

        serializer = startCallSerializer(data=request.DATA)

        if serializer.is_valid():

            serializer.save()

            return Response(serializer.data, status=status.HTTP_201_CREATED)

        else:

            return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

my serializer.py is

class startCallSerializer(serializers.ModelSerializer):

    class Meta:
        model = call
        fields = ('tutor', 'billed', 'rate', 'opentok_sessionid')

my urls.py is

urlpatterns = patterns(
    'api.views',
    url(r'^call/make-call/$','startCall', name='startCall'),
)

You should use a debugger like pdb to step through your code, watch the control flow and see what is being returned by the views. — rubayeet
– rubayeet, Commented Apr 27, 2014 at 6:19

Kwaw Annor · Accepted Answer · 2022-10-11 18:04:24Z

17

The function does not return a Response object on "GET" request. That is if request.method == 'POST' check does not pass.

@api_view(['GET', 'POST'])
def startCall(request):

    if request.method == 'POST':
        serializer = startCallSerializer(data=request.DATA)

        if serializer.is_valid():
            serializer.save()
            return Response(serializer.data, status=status.HTTP_201_CREATED)
        else:
             return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
    
    # Return Response instance if request method 
    # is not POST
    return Response({'key': 'value'}, status=status.HTTP_200_OK)

edited Oct 11, 2022 at 18:04

answered Sep 5, 2014 at 11:50

Kwaw Annor

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Comments

Cyber Square Professional · Accepted Answer · 2018-01-30 12:54:37Z

Just add

#Return this if request method is not POST
    return Response(json.dumps({'key': 'value'},default=json_util.default))

if you don't have an error code built in your application development.

My full code :

@csrf_exempt
@api_view(['GET','POST'])
def uploadFiletotheYoutubeVideo(request):
    if request.method == 'POST': 
        file_obj = request.FILES['file']#this is how Django accepts the files uploaded. 
        print('The name of the file received is ')
        print(file_obj.name)
        posteddata = request.data
        print("the posted data is ")
        print(posteddata)
        response = {"uploadFiletotheYoutubeVideo" : "uploadFiletotheYoutubeVideo"}
        return Response(json.dumps(response, default=json_util.default))
    #Return this if request method is not POST
    return Response(json.dumps({'key': 'value'},default=json_util.default))

Suraj Ghale · Accepted Answer · 2020-02-13 17:16:19Z

0

Editing the views like below should work

@api_view(['GET', 'POST'])
def startCall(request):
    if request.method == 'POST':
    serializer = startCallSerializer(data=request.data)
    data={}
    if serializer.is_valid():
        datas = serializer.save()
        data['tutor']=datas.tutor
        data['billed']=datas.billed
        data['rate']=datas.rate


    else:
        return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
    return Response(data)

answered Feb 13, 2020 at 17:16

Suraj Ghale

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Comments

Suraj Jaiswal · Accepted Answer · 2021-10-06 06:31:33Z

0

In my case, it was resolved by reordering the methods in api_view()

Original Code:

@api_view(['GET', 'POST'])
def startCall(request):

Solution 1 Updated Code:

@api_view(['POST', 'GET'])
def startCall(request):

Or else remove other methods if not in use

Solution 2 Updated Code:

@api_view(['POST'])
def startCall(request):

answered Oct 6, 2021 at 6:31

Suraj Jaiswal

411 bronze badge

Comments

owuor Chrispine · Accepted Answer · 2023-11-10 12:02:45Z

0

I noticed I had not added request.method and that was where the error was coming from

answered Nov 10, 2023 at 12:02

owuor Chrispine

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2 Comments

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