Input button in MVC asp.net

Question

How to use Input button for @Html.ActionLink?

In my cshtml I have this code:

<div>
  @Html.ActionLink("Back to menu", "HomeController")
</div>

Now I whant to use instead hyperlink button (Back to menu), input submit button, so this button:

<input class="btn" type="submit" value="Back to menu">

Thanks.

Ondrej Svejdar · Accepted Answer · 2014-04-28 07:26:35Z

2

You can't - you can use css so the link will look like button, or you can utilize Url.Action and javascript instead. I.E.:

<input class="btn" type="submit" value="Back to menu" onclick="window.location='@Url.Action("Index", "Home")';return false" />

edited Apr 28, 2014 at 7:26

answered Apr 28, 2014 at 7:07

Ondrej Svejdar

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3 Comments

Daniel K Rudolf_mag Over a year ago

Between '@Url.Action("Registration", "LoginController")'; shows Syntax error and return false underline with red color. If I remove qutes ' ' return false become ok (blue), but then ..tion=@ underline equal (=) and shows syntax error...

Ondrej Svejdar Over a year ago

I'm not sure in what context you used that (for example I don't have semicolon - ';' at the end).

Daniel K Rudolf_mag Over a year ago

I write like this: <input type="button" value="Back to Edit Menu" onclick="window.location = @Url.Action("Registracija", "LoginAdmin"); return false"/> inside = shows Syntax error

Daniel K Rudolf_mag · Accepted Answer · 2014-04-28 08:04:51Z

0

Ok, I solved it, Ondrej Svejdar thanks for advice, I use javascript and works fine:

<input class="someCss" type="button" value="Back to Edit Menu" onclick="Redirect()"/>

And under button I use this javascript:

<script type="text/javascript">
    function Redirect() {
        var url = "@Url.Action("Registration")";
        location.href = url;
    }
</script>

So result is:

enter image description here

answered Apr 28, 2014 at 8:04

Daniel K Rudolf_mag

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Comments

Manish · Accepted Answer · 2015-01-27 07:34:10Z

0

<input type="button" value="Button" />

value="button" />

answered Jan 27, 2015 at 7:34

Manish

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2 Comments

user188654 Over a year ago

Doesn't provide a solution for the problem at hand.

Lea Cohen Over a year ago

Code blocks on their own are not usually useful answers. Please explain what the code you're showing does, and why/how that code answers the question.

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