how to populate a dropdown list forms? [duplicate]

Question

help please fill in the drop down list dynamically form values from the database.

models.py:

class Gender(models.Model):     
    gender = models.CharField(
        max_length=10, 
        blank=False,
    )   

    @classmethod
    def get_gender_list(self):
        return self.objects.all()

forms.py:

class SearchFriendsForm(forms.Form):
    gender = forms.ChoiceField(
        widget=forms.Select, 
        choices=Gender.get_gender_list(),   # not worked
        #choices=(('1', '1'), ('2', '2')),  # worked
        label='Пол',
    )

friends_search.html:

{{ form.gender }}

resulting error is displayed:

'Gender' object is not iterable
Request Method: GET
Request URL:    http://127.0.0.1:8000/userprofile/friends_search/
Django Version: 1.6.2
Exception Type: TypeError
Exception Value:    
'Gender' object is not iterable
Exception Location: C:\Python33\lib\site-packages\django\forms\widgets.py in render_options, line 528

this is solve problem. thnanks!

user3607370
– user3607370

2014-05-18 09:57:38 +00:00
Commented May 18, 2014 at 9:57 — user3607370
– user3607370, Commented May 18, 2014 at 9:57

ruddra · Accepted Answer · 2014-05-18 09:39:45Z

2

In ChoiceField, choices works like this:

CHOICES=(
    ('id1', _("value1")),
    ('id2', _("value2")),
)

So, to get choices in your choice field gender, you have to build a list like above.

Here is how I do:

CHOICES=[]
for x in Gender.get_gender_list():
   CHOICES.append((x.id, x.gender))

Finally:

class SearchFriendsForm(forms.Form):
    gender = forms.ChoiceField(
        widget=forms.Select, 
        choices=CHOICES,
        label='Пол',
    )

answered May 18, 2014 at 9:39

ruddra

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