How to execute functions from a separate class?

Question

I am using Python 2.7 from the Anaconda distro. I am trying to organize a complex data integration process into different classes and functions so I can better manage it.

As a simplified example, I have some part of my process in a file called function_test.py

import pandas as pd
import numpy as np

class Perform:
    def work(self):
        test_df = pd.DataFrame(np.random.randn(10,4), columns=['a','b','c','d'])
        print "really?"
        print test_df

I want to call and execute the above logic from function_call.py which is in the same directory:

import function_test

perform = function_test.Perform
perform.work

However, when I execute function_call.py I get the following message and nothing is printed.

UMD has deleted: function_test

How do I set this example up so function_test is imported and executed so test_df is available from within function_call.py?

Any advice is appreciated.

dt0xff · Accepted Answer · 2014-06-17 17:51:52Z

1

First of, don't use old-style classes like so:

class Perform:
    pass

Use new-style classes:

class Perform(object):
    pass

Next, you should remember - work is a method of the class Perform. So you should instantiate it first:

perform = function_test.Perform()
perform.work()

Does it work now?

answered Jun 17, 2014 at 17:51

dt0xff

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2 Comments

analyticsPierce Over a year ago

It does execute and prints from inside function_test.py. How do I make the test_df available in function_call.py? I added print test_df.dtypes and I get a 'test_df' is not defined error.

dt0xff Over a year ago

You can return it from function: return test_df and use: test_df = perform.work()

Haifeng Zhang · Accepted Answer · 2014-06-17 17:56:15Z

1

add brackets.

perform = function_test.Perform()
perform.work()

answered Jun 17, 2014 at 17:56

Haifeng Zhang

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