String array converting to integer [duplicate]

Question

I have this chunk of code that I've been having problems with:

    int n = 5;
    String[] variables = new String[31];
  //user input defining the strings in the array
for(int i = 1; i < n+1; i++)
{
    System.out.print("Define variable " + i + ": ");
    variables[i] = System.console().readLine();
    System.out.println("Variable " + i + " has been set to " + variables[i]);
}
int vfirstDigit;
  //some irrelevant code excluded
for(int firstDigit = 1; firstDigit < n+1; firstDigit++)
{
    switch(firstDigit)
    {
        case 1:             
        vfirstDigit = variables[1];
        break;              
    }
}

When I call variables[1] in the switch statement, the compiler flags it as an error, saying the String array cannot be converted to an integer. Why does calling a specific string in the array convert it to an integer, when the user input must be characters? Pretty sure I'm doing something wrong here.

if your string contains JUST number, you have t parse it. Can you post up your switch statement too? — Kick Buttowski
– Kick Buttowski, Commented Jun 22, 2014 at 16:20

ak0053792 · Accepted Answer · 2014-06-22 16:22:04Z

0

Array is an object. You need to convert it in number by using method parseInt of Integer.

answered Jun 22, 2014 at 16:22

ak0053792

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Comments

TheLostMind · Accepted Answer · 2014-06-22 16:29:57Z

0

use,

vfirstDigit = Integer.parseInt(variables[1]); // vfirstDigit is an int and variables[1] returns a String. you have to convert (parse) the String to an int.

parseInt() is a static method in Integer class. It has many overloaded forms (i.e, many forms which take different arguments).It returns the integer representation of the value passed.

edited Jun 22, 2014 at 16:29

answered Jun 22, 2014 at 16:20

TheLostMind

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4 Comments

Kick Buttowski Over a year ago

how do you the content of variable contains numbers for sure?

TheLostMind Over a year ago

@KickButtowski - Then he will endup with a NumberFormatException. Its something that must be taken care by the OP.

Kalashnikov Over a year ago

Awesome, it looks like it works. Can you explain what that does please? Trying to learn :D

Kalashnikov Over a year ago

Thanks for the help guys, that cleared up a bunch of problems I've been having!

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