Query regarding svn log command line

You need to add a -l 1 to your command like this:

svn log -l 1 --search="text"

The -l flag is the shorter version of --limit:

--limit (-l) NUM

Shows only the first NUM log messages.

By first NUM log messages it means the first it hits in order from newest -> oldest.

You view some documenation on the svn log command here.

The above doesn't actually work in this case as per @bahrep's answer however as this doesn't appear to be possible using svn.exe only. I have created a python script that does it:

import xml.etree.ElementTree as ET
import subprocess
import sys

# Change the below to your url and search string
url = "http://svn.apache.org/repos/asf/spamassassin/trunk"
search_term = "160"

# Run the svn log command and get the results as xml
args = ["svn", "log",'--search="{0}"'.format(search_term), url, "--xml"]
svn_out = subprocess.check_output(" ".join(args))
svn_xml = ET.fromstring(svn_out)

try:
    # Get the latest log by revision number
    latest_log = max(svn_xml, key=lambda x : int(x.attrib["revision"]))
except ValueError:
    sys.exit("No Results Found")  # Empty svn_xml would indicate no results.

# Print log author and message
author = latest_log.find("author").text
msg = latest_log.find("msg").text
print "{0} : {1}".format(author, msg)

Which returns for me using python 2.7 in Windows:

python .\svn_redemption.py
spamassassin_role : updated scores for revision 1607021 active rules added since last mass-check

Basically it gets the xml results from the the command line output, then gets the highest revision as the result.

You'll need to change the url and the search_term variables to the ones you want, but it should work.

It looks like it's not possible with just svn.exe command-line client.

Unactual part below, see updated @Noelkd's answer!

@Noelkd's answer is not correct, as far as I can see now. Using -l 1 option limits the search query's range, not the output it produces.