I have this:
1200
3701
Trying to get this:
100ct1200
100ct3701
But got this:
100ct([0-9])([0-9])([0-9])([0-9])
Because I used regex in find & replace:
Find: ([0-9])([0-9])([0-9])([0-9])
Replace: 100ct([0-9])([0-9])([0-9])([0-9])
Actually I don't know how to express it to just add 100ct infront of the numbers and leave the rest as-it-is. Help? Thanks!
You need to use the following syntax
Find: (([0-9])([0-9])([0-9])([0-9]))
Replace: 100ct\1
Note the parentheses around the whole find expression: \1 refers to their content.
EDIT:
You can also use some shorthands for the Find expression:
Find: (\d{4})
It means "match 4 digits".
\1 is only a reference to the content of the first parentheses group. Try it!
(([0-9])([0-9])([0-9])([0-9])) in steps. Remove unneeded brackets to give ([0-9][0-9][0-9][0-9]). Change to (\d\d\d\d) and finally to (\d{4})Comments use mini-Markdown formatting: The post author will always be notified of your Just wants to add quotation marks so it will look like this: "Comments use mini-Markdown 21formatting:" "The post author w65ill always be notified of your" It's tricky since it contains characters and numbers and strings.Your find and replace commands should be,
Find: ([0-9][0-9][0-9][0-9])
Replace: 100ct$1
$1 or \1 or #1 according to your tool.
Find: ([0-9][0-9][0-9][0-9])
Replace: 100ct$1 or 100ct\1 depending on the language (not sure what syntax Notepad++ uses).
$1 or '\1` is just a reference to what you matches in the first set of () of your regex. ($2 or \2 would match the second set of (), and so on...).