XSLT get array element by id

Question

I have XSLT:

<xsl:template match="/">
    <!--<FLC_OKVEDCODE>-->
    <xsl:variable name="valArray" select="//NodeA | //NodeB | //NodeC"/>
    <xsl:variable name="valResArray">
        <result_value>TextA</result_value>
        <result_value>TextB</result_value>
        <result_value>TextC</result_value>
    </xsl:variable>
    <xsl:variable name="resArray" select="document('')//xsl:variable[@name= 'valResArray']/*"></xsl:variable>

    <xsl:for-each select="$valArray">
        <xsl:if test="string-length(normalize-space(text())) = 0">
            <ERROR>
                <Err1><xsl:value-of select="position()"></xsl:value-of></Err1>
                <Err2><xsl:value-of select="$resArray[1]"></xsl:value-of></Err2>
                <Err3><xsl:value-of select="$resArray[2]"></xsl:value-of></Err3>
                <Err4><xsl:value-of select="$resArray[3]"></xsl:value-of></Err4>
                <Err5><xsl:value-of select="$resArray[position()]"></xsl:value-of></Err5>
            </ERROR>
        </xsl:if>
    </xsl:for-each>
    <!--</FLC_>-->
</xsl:template>

It have to check NodeA, NodeB and NodeC if they are empty - create error XML. In my test NodeB is empty, but result is:

<ERROR>
    <Err1>2</Err1>
    <Err2>TextA</Err2>
    <Err3>TextB</Err3>
    <Err4>TextC</Err4>
    <Err5>TextA</Err5>
</ERROR>

Why Err5 is TextA, if position() return 2 and $resArray[2] (printed at ) is TextB??

Arkady · Accepted Answer · 2014-07-11 13:39:27Z

2

After that problem ate my brain, solution was very simple:

Adding:

<xsl:variable name="temppos" select="position()"></xsl:variable>

between Err4 and Err5. It looks like it automatically puts array as parameter for such functions as "position", and do it with closest array. So, "position()" of "resArray" was still 1, and that is why there was this result.

That is explanation that I guess. Still, I disappointed with handling arrays in XSLT.

answered Jul 11, 2014 at 13:39

Arkady

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2 Comments

Ian Roberts Over a year ago

The issue is that a predicate changes the context - $resarray[position()] evaluates the position() predicate once in the context of each node in $resarray, whereas what you want to do is capture the position() value in the outer context (the for-each) and use that value inside the predicate. As you've discovered, the simplest way to do this is to use a variable.

Ian Roberts Over a year ago

A numeric predicate [N] is equivalent to [position() = N], so [position()] means [position() = position()] which is always true.

michael.hor257k · Accepted Answer · 2014-07-11 13:40:47Z

2

Why Err5 is TextA, if position() return 2

Why do you think that position() returns 2? The truth is that the expression:

$resArray[position()]

means "all nodes of $resArray that have a non-zero (i.e. true) position". Which is true of all nodes of $resArray.

Therefore the expression:

<xsl:value-of select="$resArray[position()]"/>

will return the value of the first node of the returned node-set (i.e. TextA) in XSLT 1.0, and the values of all matching nodes (i.e. TextA TextB TextC) in XSLT 2.0.

answered Jul 11, 2014 at 13:40

michael.hor257k

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2 Comments

Arkady Over a year ago

Because "position()" 3 lines above returned 2. And I need position of iterable array, but didn't know how to resolve it, where to read about it and etc.

michael.hor257k Over a year ago

@Arkady That's not how it works. The position() inside the predicate is the position of the node being tested. You can see this if you try $resArray[position() = 2], for example.

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