61

here is my string:

var str = "This is my \string";

This is my code:

var replaced = str.replace("/\\/", "\\\\");

I can't get my output to be:

"This is my \\string"

I have tried every combination I can think of for the regular expression and the replacement value.

Any help is appreciated!

0

9 Answers 9

53

Got stumped by this for ages and all the answers kept insisting that the source string needs to already have escaped backslashes in it ... which isn't always the case.

Do this ..

var replaced = str.replace(String.fromCharCode(92),String.fromCharCode(92,92));
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4 Comments

i do not understand why but this doesn't work for me. here is a jsfiddle, care to help. jsfiddle.net/a2nsL4bv
@TimarIvoBatis , i just came across this comment of yours, you need to escape the backslash. stackoverflow.com/questions/8351547/…
Not sure why this has 49 upvotes. The String.fromCharCode calls are unnecessary. The problem in the question is that the string literal "This is my \string" contains zero backslashes. You can’t replace what isn’t in the string to begin with. The string variable str may contain backslashes which then can simply be replaced like str.replace(/\\/g, "\\\\"), or str.replaceAll("\\", "\\\\"). But if you don’t get your literals correctly to begin with (as written in the question), this answer won’t help.
The charcode list in somebody needs it : asecuritysite.com/coding/asc2
52

The string doesn't contain a backslash, it contains the \s escape sequence.

var str = "This is my \\string";

And if you want a regular expression, you should have a regular expression, not a string.

var replaced = str.replace(/\\/, "\\\\");

2 Comments

var replaced = str.replace(/\\/g, "\\\\"); not thtat the /g global flag is necessary, but if you want to replace every instance of backslash, this is how you'd do it.
works fine form me in sqllite to save JSON.stringfy() to remove back slash . Thanks
13

The problem is that the \ in your first line isn't even recognized. It thinks the backslash is going to mark an escape sequence, but \s isn't an escape character, so it's ignored. Your var str is interpreted as just "This is my string". Try str.indexOf("\\") - you'll find it's -1, since there is no backslash at all. If you control the content of str, do what David says - add another \ to escape the first.

4 Comments

The problem is that I don't control the value. Its actual a windows path that I'm dealing with ( \wp-content\photos\image123.jpg ). The string is given to me as "\wp-content\photos\image123.jpg" but I can't do anything with it because the backslashes disapear. I understand they are being parsed as escape characters but I don't know how to fix it.
Either you are getting broken JS (in which case you can't fix it) or you are getting a string in some other language and outputting it to JS without escaping special characters first, in which case you have to fix it there.
Agreed - the only way escape sequences can get into a string is if the string is constructed in javascript. If it's coming from a form field, ajax response, query string, etc, it shouldn't need escaping. When you say "the string is given to me as..." - HOW is it actually provided to you?
@Tesserex I have try the str.indexOf("\\"), and I got a json-string, which nested a json-string with the backslash inside. It's really suck...
9

var a = String.raw`This is my \string`.replace(/\\/g,"\\\\");
console.log(a);

Result:

This is my \\string

Comments

5

In case you have multiple instances or the backslash:

str.split(String.fromCharCode(92)).join(String.fromCharCode(92,92))

Comments

2

Use this

str.replace(/(\s)/g,function($0){return $0==' '?' ':'\\s'})

or

str.replace(/ /g,'something').replace(/\s/g,'\\s').replace(/something/g,' ');

'something' it may be a combination of characters that is not in string

var str=' \s';  
  str.replace(/\s/g,'\\s'); 
// return '\\s\\s'   
  str.replace(/ /g,'SpAcE').replace(/\s/g,'\\s').replace(/SpAcE/g,' ');
// return ' \\s' 

Comments

1

I think the confusion is coming from how a string is displayed in the browser console. (I just checked chrome)

let myString = "This is my \string";

Here myString is actually doesn't include any backslash char. It includes \s sequence which resolves to s.

So If you display your string in the console:

> myString => 
"This is my string"

> console.log(myString) 
This is my string

The following string though has only 1 backslash in it:

let myString = "This is my \\string";


//string representation includes the escape char as well. So we see double backslashes.  
> myString => 
"This is my \\string" 

//When you print it, the escape char is not there. 
> console.log(myString) 
This is my \string 

So finally if you want to replace backslash char with 2 backslashes you can do this:

let myNewStringWith2Backslashes= myString.replace("\\","\\\\")

Comments

-1

If use case is to replace some values in the toString of a function, and convert the string back to a valid function.

var exFnStr1 = exFn.toString();

var exFnStr = "";
var quoteStarted = false;
for(i = 0; i < exFnStr1.length; i++) {
    var iChar = exFnStr1.charAt(i);
    var oChar = exFnStr1.charAt(i);
    var currentCharCode = exFnStr1.charCodeAt(i);
    if(quoteStarted) {
        if(currentCharCode === 9) oChar = "tabChar";
        if(currentCharCode === 10) oChar = "newlineChar";
    }
    //console.log(iChar+"->"+currentCharCode+"->"+oChar)
    exFnStr += oChar;

    if(currentCharCode === 34) {
        if(quoteStarted) quoteStarted = false;
        else quoteStarted = true;
    }
}
console.log(exFnStr);

//TODO - replace values in the string

exFn = new Function('return ' + exFnStr)();

Comments

-2

I haven't tried this, but the following should work

var replaced = str.replace((new RegExp("\s"),"\\s");

Essentially you don't want to replace "\", you want to replace the character represented by the "\s" escape sequence.

Unfortunately you're going to need to do this for every letter of the alphabet, every number, symbol, etc in order to cover all bases

1 Comment

"\s" is "s", so this will get any other s characters too. You'd end up prefixing every character in the string with a `` unless the sequence was a control character.

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