I tried such code to redirect standart output to the file:
subprocess.Popen('my command', cwd='my path', shell=True, stdout=stdout.txt, stderr=stdout.txt)
But got error: NameError: name 'stdout' is not defined
I use python version 2.5.2
2 Answers
Open the file first and use a to append if you want to keep a record of all output/errors or use w to overwrite each time:
with open("stdout.txt","a+") as stdout:
subprocess.Popen('my command', cwd='my path', shell=True, stdout=stdout, stderr=stdout)
Using with will automatically close your file.
answered Jul 28, 2014 at 13:33
Padraic Cunningham
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7 Comments
chepner
Popen doesn't block until my command completes, though, so ensure you don't leave the with statement before the command completes.
khris
I try this, but got
AttributeError: 'str' object has no attribute 'fileno' Padraic Cunningham
How are you using it exactly
idjaw
Hi @PadraicCunningham. Thoughts on maybe adding the suggestion (or show an alternative solution) to this solution to not use
shell=True? Understandably it's matching the OP exact code. But I came across this answer to help out someone else, and having shell != True would probably be more appropriate for a more robust solution.Padraic Cunningham
@idjaw, hi, I will update with a few more options tomorrow. A s far as shell=True goes it actually depends on what you are running, for windows you actually need it.
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stdoutargument could take a file name instead of a file handle (note: it can't), you would have to quote the text. As it is, Python thinks you are trying to access thetxtattribute of an object referenced bystdout, not specifying a file name of "stdout.txt".