Regex match but exclude character from capture group

Question

I have the following regex:-

^(?:\[ [^\]]+ \]) ([\-\£]{1,2}[0-9]+\.[0-9][0-9]?)?

And the following text:-

John Doe
+++++++++++++++++++++++++++++++++++++++++++
Blah blah
+++++++++++++++++++++++++++++++++++++++++++
[ √ ] £3.00 Red
[ √ ] £2.00 Blue
[ √ ] £55.55 Yellow
[ √ ] -£41.75 PAYMENT
[ √ ] £5.00 Green
[ √R ] £10.00 Pink
+++++++++++++++++++++++++++++++++++++++++++
Belugh
+++++++++++++++++++++++++++++++++++++++++++
Blah blah
Blah

The regex works ok and matches:-

£3.00
£2.00
£55.55
-£41.75
£5.00
£10.00

What I want to do though is to have the regex match the '£' but not return it in the capturing group.

So the results would be like this:-

3.00
2.00
55.55
-41.75
5.00
10.00

The important bit is the '-' character which should remain, but occurs before the '£' character.

Theres a fiddle here

That's not possible within the regex, use your environments capabilities to go through the matches and "clean up" anything you don't want. Regexes might help with the cleaning up, but I don't think you can do this with 1 regex. — asontu
– asontu, Commented Aug 25, 2014 at 9:48

asontu · Accepted Answer · 2014-08-25 09:53:06Z

5

Best you can do is this:

^(?:\[ [^\]]+ \]) (-?)[\£]([0-9]+\.[0-9][0-9]?)?

And then extract group 1 and group 2 from the matches and append them in the language/environment you're working in.

Demo

answered Aug 25, 2014 at 9:53

asontu

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asontu Over a year ago

I actually prefer debuggex.com, particularly when doing more complicated stuff. But regex101 has some nice features too :)

Eddie Davidson · Accepted Answer · 2021-01-04 13:12:38Z

0

I did this by including the "£" in the capture group and then simply replacing that symbol with "nothing" from the matched results in the language I'm working in.

answered Jan 4, 2021 at 13:12

Eddie Davidson

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