python 3 recursive function that prints in order

Question

I want to print my list in order, but it keeps printing the first value

def print_order(s):
    if not s: 
        return
    print(s[0])
    print_order(s[:-1])

for example I have a list [1, 2, 3, 4, 5, 6, 7] I want it to be printed out as

lily · Accepted Answer · 2014-09-30 23:38:24Z

1

You are taking the last element off instead of the first. Try changing the recursive call's argument to s[1:].

answered Sep 30, 2014 at 23:38

lily

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1 Comment

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molbdnilo · Accepted Answer · 2014-09-30 23:39:21Z

0

The slice s[:-1] is all elements except the last.

You want s[1:], which is all elements except the first.

answered Sep 30, 2014 at 23:39

molbdnilo

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