How to hidden the output of Linux command launched from shell_exec()

Question

Hi guys this is my code

<?php
  $res = shell_exec('curl  http://www.example.com');

I launched it from the terminal using this command

php script.php

and this is the output:

% Total    % Received % Xferd  Average Speed   Time    Time     Time  Current
Dload  Upload   Total   Spent    Left  Speed
100  1270  100  1270    0     0   5515      0 --:--:-- --:--:-- --:--:-- 11545

I don't want to see nothing how can i do??

are you always making calls to curl? if thats the case you should be using phps implementation of curl — castis
– castis, Commented Nov 20, 2014 at 16:18

Kevin M Granger · Accepted Answer · 2014-11-20 16:27:43Z

1

You are seeing that output because curl outputs its current progress to STDERR.

You could solve this with a redirection if you want to ignore it:

$res = shell_exec('curl  http://www.example.com 2>/dev/null');

Or, in the shell level:

$ php script.php 2>/dev/null

answered Nov 20, 2014 at 16:27

Kevin M Granger

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1 Comment

b1zzu Over a year ago

Thank thisbis the best way

Steve · Accepted Answer · 2014-11-20 16:18:30Z

0

You can use output buffering

ob_start();
$res = shell_exec('curl  http://www.example.com');
ob_end_clean();

answered Nov 20, 2014 at 16:18

Steve

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