AWK Assignment to variable

Question

I am looking for assignment of value of variable to another variable in awk.

Below is the example

if (substr($0,1,1) == "4") 
{
    COUNT_DETAIL_SEG++
    SUM_OF_DETAIL_RCDS=$(COUNT_DETAIL_SEG)
    print "Sum of detail records is" SUM_OF_DETAIL_RCDS
}

Suppose if 1st character of line comes out to be "4" then i want to increment value of COUNT_DETAIL_SEG and assign this value to SUM_OF_DETAIL_RCDS and thereby print it. But i am unable to retain this value. Can anyone have any idea about this?

Gilles Quénot · Accepted Answer · 2014-12-24 17:50:36Z

1

I think instead of

SUM_OF_DETAIL_RCDS=$(COUNT_DETAIL_SEG)

you want :

SUM_OF_DETAIL_RCDS=COUNT_DETAIL_SEG

because in awk, when you put $(INT), you refer no the N'th column of the current input line.

edited Dec 24, 2014 at 17:50

answered Dec 24, 2014 at 17:25

Gilles Quénot

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1 Comment

Gilles Quénot Over a year ago

Thanks to accept the answer if it fit your needs. That's hos stackoverflow work.

jim mcnamara · Accepted Answer · 2014-12-24 17:32:51Z

0

Maybe you want to do this at the start of the awk statement. @sputnick is on the right track.

awk -v var="$bash_var" '{ awk code here}'

This will use the awk internal variable var instead of the shell variable bash_var.

answered Dec 24, 2014 at 17:32

jim mcnamara

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