How can I write into a file the output of a command but also include the command at the beginning of a file?
eg:
grep -nrs 'blah' . >/home/ca/out.txt
so that the file shows
grep -nrs 'blah' . >/home/ca/out.txt
./something.cpp:1329: if(blah)
to leave a blank line between?
grep -nrs 'blah' . >/home/ca/out.txt
./something.cpp:1329: if(blah)
....
Thank you
You can store command line and result both in a file using bash -vc like this:
bash -vc "grep -nrs 'blah' ." >& /home/ca/out.txt
-v is for verbose mode in bash that outputs full command before executing it.-c is for running a command from command line>& is for redirecting both stdout and stderrAnother approach is store command line in an array:
arr=(grep -nrs 'blah' .)
{ printf "%q " "${arr[@]}"; echo; echo; "${arr[@]}"; } >& /home/ca/out.txt
You can use logsave (usage) to log the output together with a timestamp and the command, e.g.:
logsave -a output.txt ls
Saves the output of the ls command into output.txt:
Log of ls
Thu Jan 29 16:49:25 2015
[output of command]
Thu Jan 29 16:49:25 2015
----------------
If you use it in a bash-script you can first write and echo line and then add the output to the file:
echo "grep -nrs 'blah' ." > /home/ca/out.txt
grep -nrs 'blah' . >> /home/ca/out.txt
Use script command to save both command and output in same file, as follows
script -a mycommands.txt
Once the section to be recorded is complete, type exit in terminal to exit the program.
script- I love that command, but haven't used it for years; and if you don't remember the name, hard to do anaproposto find it.