"bash -c" doesn't export vars from sourced scripts

Question

I have an inclusion file test.inc:

export XXX=xxx

I use it when call bash to interpret a string:

bash -c ". test.inc; echo $XXX"

But the variable is not set at the point of echo command. If I do 'export' I can see it though:

bash -c ". test.inc; export"

Shows

declare -x XXX="XXX"

How do I make my first command see the exported variables from sourced files when I use bash -c syntax?

tripleee · Accepted Answer · 2015-02-02 10:20:10Z

1

You are using double quotes. Therefore your current shell expands $XXX long before the bash -c instance sees it. Switch to single quotes, or escape the dollar sign.

answered Feb 2, 2015 at 10:20

tripleee

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