I have a python list as follows:
data = [1,2,3,4,5]
I want to write it in text file as follows:
1,2,3,4,5 ##as comma delineated.
I tried as:
with open ('data.txt', 'w') as fo:
for d in data:
fo.write(str(d) + '\n')
But it wrote data as follows:
1
2
3
4
5
How would you do it guys?
EDIT:
I will also have other lists obtained from for-loop, so all the one list i.e., 1,2,3,4,5 have to be adjusted in one line. In addition, I need faster performance.
It looks like you want a CSV (comma separated value) file as your output. You can use the CSV python module.
An example could look like:
import csv
data = [1,2,3,4,5]
with open('test.csv', 'w') as csvfile:
writer = csv.writer(csvfile, delimiter=",")
writer.writerow(data)
You can use the join method
with open ('data.txt', 'w') as fo:
fo.write(','.join(str(i) for i in data))
The simplest way is to convert the list to a joined string, then write:
str_data = ','.join(str(i) for i in data)
with open('data.txt', 'w') as fo:
fo.write(str_data)
In case if the list is too long to convert it all to the string:
with open('data.txt', 'w') as fo:
for idx, item in enumerate(data):
if idx: # don't need a comma before the list
fo.write(',')
fo.write(item)
Update: that all said, aus_lacy's suggestion about CSV seems the best.
data = [1, 2, 3, 4, 5]
with open ('data.txt', 'w') as fo:
fo.write(','.join([str(n) for n in data]))
A simple way
data=[1,2,3,4,5]
with open ('data.txt', 'w') as fo:
for d in data:
if d!=data[len(data)-1]:
fo.write(str(d)+',')
else:
fo.write(str(d))
Not so simple one:
dat=','.join([str(t) for t in data])
fo.write(dat)
