Python - Casting Error

Question

I'm trying to code a program that will print the total price after a discount. If the price paid is over 100, it will knock off 20%. At the end of the program, I receive this error:

if paid>=100:
    TypeError: unorderable types: str() >= int()

Here is my Code:

paid=input('How much did you pay? ')
if paid>=100:
    actualPay=100*1.25 #20% off total, 100/0.80 = 1.25
    print(actualPay)

Bhargav Rao · Accepted Answer · 2015-03-04 18:28:04Z

5

Cast the input to an int

paid=int(input('How much did you pay? '))

input always returns a string. You need to explicitly cast it.

Ex:

paid=int(input('How much did you pay? '))
if paid>=100:
    actualPay=100*1.25
    print(actualPay)

A better way would have a try and except block.

try:
    paid=int(input('How much did you pay? '))
    if paid>=100:
        actualPay=100*1.25
        print(actualPay)    
except TypeError:
        print "Please enter a valid input."

answered Mar 4, 2015 at 18:28

Bhargav Rao

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3 Comments

Klodiano Over a year ago

Thanks! I don't know how I missed that.

Robert Jacobs Over a year ago

Input does not always return an string. input is Equivalent to eval(raw_input(prompt)). Maybe the input cannot be is converted to\ an integer.

Bhargav Rao Over a year ago

@RobertJacobs Maybe you are using Python2. The OP is using Py3 :). Check the link for the python3 input function

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