Access value from another function in php

Question

I have a function skipCopy:

public function skipCopy($skipcopy){
    $skipcopy1 = $skipcopy;
}

Now I wish to use the value in $skipcopy1 in the copy() function with structure as belows:

protected function copy($id, $srcip, $srcusername, $srcpassword, $tgtip, $tgtusername, $tgtpassword, $publish) {
     //use $skipcopy1 here. Do this without passing the value as parameter. as all the parameters in the copy function are mandatory.
 }

How can I achieve this.

Both the functions are of same PHP class.

Rikesh · Accepted Answer · 2015-03-12 06:22:00Z

1

You can use global keyword as mention in another answers or else define that variable as member of the class,

protected $skipcopy;
public function skipCopy($skipcopy){
    $this->skipcopy = $skipcopy;
}
protected function copy($id, $srcip, $srcusername, $srcpassword, $tgtip, $tgtusername, $tgtpassword, $publish) {
   echo $this->skipcopy; //You can now access this variable.
 }

answered Mar 12, 2015 at 6:22

Rikesh

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Comments

Mihir Bhatt · Accepted Answer · 2015-03-12 06:19:42Z

0

Define $skipcopy1 as global in copy() function like

global $skipcopy1;

answered Mar 12, 2015 at 6:19

Mihir Bhatt

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Comments

Utkarsh Dixit · Accepted Answer · 2015-03-12 06:24:02Z

0

Just use global keyword OR you could object to store the values. Use the code below

protected function copy($id, $srcip, $srcusername, $srcpassword, $tgtip, $tgtusername, $tgtpassword, $publish) {
global $skipcopy1;
 }

Hope this helps you

answered Mar 12, 2015 at 6:24

Utkarsh Dixit

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Comments

testo · Accepted Answer · 2015-03-12 06:38:37Z

0

public function skipCopy($skipcopy){
  global $skipcopy1;
  $skipcopy1 = $skipcopy;
}

protected function copy($id, $srcip, $srcusername, $srcpassword, $tgtip, $tgtusername, $tgtpassword, $publish) {
  global $skipcopy1;
  // use it
}

edited Mar 12, 2015 at 6:38

answered Mar 12, 2015 at 6:25

testo

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2 Comments

Utkarsh Dixit Over a year ago

there is no need for global keyword skiCopy() function

testo Over a year ago

sorry, I didn't see the 'public' and 'protected' keyword and read that it is class code.

Umair Ahmed · Accepted Answer · 2015-03-12 06:43:29Z

0

Declare this Variable in constructor like

public function __construct(){
$this -> skipcopy1 = '';
}

answered Mar 12, 2015 at 6:43

Umair Ahmed

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