Basic Python While loop compound conditional evaluation

Question

In Python IDLE Shell it seems I cannot use a compound conditional expression and a while loop. I tried it within brackets too. Take these two examples:

k=0
m=0
while k<10 & m<10:
    print k
    k +=1
    m+=1

This doesn't evaluate the second condition. But if I write

 while k<10:
    print k
    k+=1

This does work. Is there a way I could achieve the first block of code with the "and" operator. I have done it in Java. Do I just need to put together "if" statements to achieve the same functionality in Python?

The answer to your question is given below by Deniz Dogan. But usually constructing while (or for) loops like this, i. e. by using a counter and incrementing it up to a certain value, is not Pythonic. You rather do a for x in range(10) or even better, for item in list_of_items, letting Python handle the iteration. — Tim Pietzcker
– Tim Pietzcker, Commented Jun 9, 2010 at 14:15
To add to Tim's comment, you can use for idx, elem in enumerate(my_list) to get both the 0-based "counter" in idx and the element at that index of the list in elem. — Deniz Dogan
– Deniz Dogan, Commented Jun 9, 2010 at 14:18

Deniz Dogan · Accepted Answer · 2010-06-09 14:00:28Z

7

& should be and. & is the bitwise AND operator.

answered Jun 9, 2010 at 14:00

Deniz Dogan

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