I want to call the function multiple time and use it's returned argument everytime when it's called. For example:
def myfunction(first, second, third):
return (first+1,second+1,third+1)
1st call: myfunction(1,2,3)
2nd call is going to be pass returned variables: myfunction(2,3,4) and loop it until defined times. How can I do such loop? Thank you!
a,b,c = 1,2,3
while i<n:
a,b,c = myfunction(a,b,c)
i +=1
v = (1,2,3) and v = myfunction(*v).def myF(x,y,z,i):
print x, i
while i:
x += 1
i -= 1
return myF(x,i)
This will keep calling myF until i is 0 which will break the while loop, example:
>>> myF(1,10)
1 10
2 9
3 8
4 7
5 6
6 5
7 4
8 3
9 2
10 1
11 0
For three arguments, you can do as follows:
>>> def myF(x,y,z,i):
print x,y,z,i
while i:
i -= 1
x,y,z = map(lambda s:s+1,(x,y,z))
return myF(x,y,z,i)
>>>
>>>
>>> myF(1,1,1,10)
1 1 1 10
2 2 2 9
3 3 3 8
4 4 4 7
5 5 5 6
6 6 6 5
7 7 7 4
8 8 8 3
9 9 9 2
10 10 10 1
11 11 11 0
return in the loop breaks the loop on the first iteration.while i loop at all? And what's up with the inconsistent y and z arguments?
while loop is keep calling myF function i times...and what is it with the x and z???...why you said inconsistent ?
for i in range(n): print myfunction(i,i+1,i+2)