Why string type is not converting to int type?

Question

I want to add two numbers. I am getting values from button in my textbox. I also succeeded in splitting string into substrings and store values of these substrings in variables. But i am not able to convert string type to integer type. That results in concatenation not in addtion. Note : I am using MVC to perform this task. And in model value1 and value2 is string type in model Here is my code snippet:

if (button == "1"){
    if (model.textBox == "" || model.textBox == null || model.textBox.ToLower().Contains("please enter value")){
        model.textBox = "1";
    } else {
        model.textBox += "1";
    }
}
if (button == "2") {
    if (model.textBox == "" && model.textBox == null) {
        model.textBox = "2";
    } else {
        model.textBox += "2";
    }
if (button == "+") {
    if (model.textBox == "" && model.textBox == null){
        model.errormsg = "Please enter a number ";
    } else {
        model.textBox += "+";
    }
if (button == "=") {
    if (model.textBox.Contains("+")) {
        model.value1 = (model.textBox.Split('+'))[0];
        int value1 = int.Parse(model.value1);
        model.value2 = (model.textBox.Split('+'))[1];
        int value2 = int.Parse(model.value2);
         model.textBox = model.value1 + model.value2;
    }
return View(model);

Your adding the model values (which are typeof string), it the int values you declare - model.textBox = (value1 + value2).ToString(); — user3559349
– user3559349, Commented Jul 27, 2015 at 13:14

israel altar · Accepted Answer · 2015-07-27 13:13:49Z

5

If i got you correctly all you need to do is:

model.textBox = (value1 + value2).ToString();

answered Jul 27, 2015 at 13:13

israel altar

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6 Comments

adeel Over a year ago

Already my value are of string type. I want to convert them to integer. So that values must be added not concatenated.

israel altar Over a year ago

Yes, but value1 is in and also value2 - after you added them it makes on the sum the ToSring() action.

adeel Over a year ago

Please provide me some more help and detail. I am not getting the desired result. It still concatenate the value 1 and value2, not adding value1 and value2.

israel altar Over a year ago

please tell me where do you see the concatination? in which part or code snippet?

adeel Over a year ago

if (button == "=") { if (model.textBox.Contains("+")) { model.value1 = (model.textBox.Split('+'))[0]; model.value2 = (model.textBox.Split('+'))[1]; model.textBox = (model.value1 + model.value2).ToString();} this code snippet gives me concatenation result: if entered values are 1 and 2 then result would be 3 but this gives me result 12

|

Arturo Torres Sánchez · Accepted Answer · 2015-07-27 13:28:53Z

1

model.textBox is of type string, so, when you do model.textBox += "1"; the only possible operation is concatenation.

To add them as integers you first need to convert your textBox to int.

Something like the following will work:

model.textBox = (int.Parse(model.textBox) + 1).ToString();

answered Jul 27, 2015 at 13:28

Arturo Torres Sánchez

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Comments

Jeff · Accepted Answer · 2015-07-27 13:52:56Z

0

Try using int.Parse(textBox.Text).

It will crash if there is a non-numeric character in the string, but that's nothing a try-catch block won't fix.

Hope this helps!

answered Jul 27, 2015 at 13:52

Jeff

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Comments

adeel · Accepted Answer · 2015-07-28 08:16:16Z

 if (button == "=") {
    if (model.textBox.Contains("+")) {
        model.value1 = (model.textBox.Split('+'))[0];
        int value1 = int.Parse(model.value1);
        model.value2 = (model.textBox.Split('+'))[1];
        int value2 = int.Parse(model.value2);
         model.textBox = model.value1 + model.value2;
    }

Replace above code snippet with below code snippet:

if (button == "=")
            {
                if (model.textBox.Contains("+"))
                {
                    model.value1 = (model.textBox.Split('+'))[0];

                    model.value2 = (model.textBox.Split('+'))[1];

                    model.textBox1 = (int.Parse(model.value1) + int.Parse(model.value2)).ToString();


                }

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