Laravel 5.1: How to upload multiple files from three different file input fields?

Question

I have a form in which user should at least select one file to be uploaded. I have three file input fields like this:

            <div class="form-group col-lg-4">
                {!! Form::label('file1', 'Select file 1', ['class' => 'control-label']) !!}
                {!! Form::file('files[]', ['id'=>'file1']) !!}
            </div>
            <div class="form-group col-lg-4">
                {!! Form::label('file2', 'Select file 2', ['class' => 'control-label']) !!}
                {!! Form::file('files[]', ['id'=>'file2']) !!}
            </div>
            <div class="form-group col-lg-4">
                {!! Form::label('file3', 'Select file 3', ['class' => 'control-label']) !!}
                {!! Form::file('files[]', ['id'=>'file3']) !!}
            </div>

I should validate the presence of at least one file and the mime types in a form request. Then in the store method of the related form controller, the original file names should be stored in the three corresponding database fields(namely file1, file2, file3).

How can I implement this?

@AliErfani why didn't the link help? It describes in details the process of uploading multiple files in Laravel and how to implement your store method — jedrzej.kurylo
– jedrzej.kurylo, Commented Aug 11, 2015 at 11:18
@jedrzej.kurylo It describes multiple file uploads from one field. I should validate each file separately then save the original name of each file to the database — Ali Erfani
– Ali Erfani, Commented Aug 11, 2015 at 11:24
You'll get the original name of each field using the method described in the link — jedrzej.kurylo
– jedrzej.kurylo, Commented Aug 11, 2015 at 12:04

Ali Erfani · Accepted Answer · 2015-08-11 12:33:02Z

4

After some searching around I finally came up with a solution. First of all I modified the view to look like this:

<div class="form-group col-lg-4">
            {!! Form::label('file1', 'Select file 1', ['class' => 'control-label']) !!}
            {!! Form::file('file1', ['id'=>'file1']) !!}
        </div>
        <div class="form-group col-lg-4">
            {!! Form::label('file2', 'Select file 2', ['class' => 'control-label']) !!}
            {!! Form::file('file2', ['id'=>'file2']) !!}
        </div>
        <div class="form-group col-lg-4">
            {!! Form::label('file3', 'Select file 3', ['class' => 'control-label']) !!}
            {!! Form::file('file3', ['id'=>'file3']) !!}
        </div>

Then in the controller I used your suggested code:

$files =[];
        if ($request->file('file1')) $files[] = $request->file('file1');
        if ($request->file('file2')) $files[] = $request->file('file2');
        if ($request->file('file3')) $files[] = $request->file('file3');
        foreach ($files as $file)
        {
            if(!empty($file)){
                $filename=$file->getClientOriginalName();
                $file->move(
                    base_path().'/public/uploads/', $filename
                );
            }

        }

answered Aug 11, 2015 at 12:33

Ali Erfani

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1 Comment

Hola Over a year ago

what if I have three different fields in database? So How i'm gonna 3 different images store it in database?

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