How to find and count in MongoDB for specific items?

Question

I would like to count the total number of each type of responses associated with each ID in the following JSON result that I am extracting from MongoDB:

{
  "test": [
    {
      "ID": 4, 
      "response": "A"
    }, 
    {
      "ID": 4, 
      "response": "B"
    }, 
    {
      "ID": 1, 
      "response": "A"
    }, 
    {
      "ID": 3, 
      "response": "B"
    }, 
    {
      "ID": 2, 
      "response": "C"
    }
  ]
}
// and so on...

So for example, I would like to structure the JSON into something like this:

{
    "test": [
        {
            "ID": 4,
            "A": 1,
            "B": 1
        },
        {
            "ID": 3,
            "B": 1
        },
        {
            "ID": 2,
            "C": 1
        },
        {
            "ID": 1,
            "A": 1
        }
    ]
}

My query looks something like this because I was just testing and trying to tally responses just for ID 4.

surveyCollection.find({"ID":4},{"ID":1,"response":1,"_id":0}).count():

But I get the following error: TypeError: 'int' object is not iterable

It is generally not a good idea to edit your post with given answer — Sede
– Sede, Commented Aug 13, 2015 at 21:30

Sede · Accepted Answer · 2015-08-13 20:16:25Z

1

What you need is use the "aggregation framework"

surveyCollection.aggregate([
    {"$unwind": "$test" }, 
    {"$group": {"_id": "$test.ID", "A": {"$sum": 1}, "B": {"$sum": 1}}},
    {"$group": {"_id": None, "test": {"$push": {"ID": "$ID", "A": "$A", "B": "$B"}}}}
])

From pymongo 3.x the aggregate() method returns a CommandCursor over the result set so you may need to convert it first into list.

In [16]: test
Out[16]: <pymongo.command_cursor.CommandCursor at 0x7fe999fcc630>

In [17]: list(test)
Out[17]: 
[{'_id': None,
  'test': [{'A': 1, 'B': 1},
   {'A': 1, 'B': 1},
   {'A': 1, 'B': 1},
   {'A': 2, 'B': 2}]}]

Use return list(test) instead

edited Aug 13, 2015 at 20:16

answered Aug 13, 2015 at 19:49

Sede

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