Show dynamic website on DIV or other element form, php, php function

Question

I have a page page1.html with a form. I POST and receive the values of the inputs on page2.php.

To explain the matter the inputs will send: (Values are NOT always the same)

$title = "This is a Title";
$url = "www.this_is_url.com";
$message = "This is a message";

Then (page2.php):

$title = $_POST['title'];
$url = $_POST['url'];
$message = $_POST['message'];

So I take the values and with the function myfunction() create and print a new page (with all the tags of a website, from <Doctype> until </html>)

What I want is to display this "new page" (without creating a file) on a div or other element of the page2.php.

So here´s the code of page2.php

<?php

if($_POST)
{

function myfunction() {

$title = $_POST['title'];
$url = $_POST['url'];
$message = $_POST['message'];

echo '<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><head><title>Title WEB</title><meta http-equiv="content-type" content="text/html;charset=utf-8" />';
echo '<style> body { width: 100%; margin: 0; padding: 0; } </style></head><body>';
echo "<br />" . $title . "<br /><br />" . $url . "<br /><br />" . $message;
echo "</body></html>"

}

echo '<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><head><title>Title WEB</title><meta http-equiv="content-type" content="text/html;charset=utf-8" />';
echo '</head><body>';
echo "<div>";

myfunction();

echo "</div>";
echo "</body></html>"
}   

?>

Try to declare your function outside the if block.

Berriel
– Berriel

2015-08-14 23:56:58 +00:00
Commented Aug 14, 2015 at 23:56 — Berriel
– Berriel, Commented Aug 14, 2015 at 23:56

Wild Widow · Accepted Answer · 2015-08-15 00:12:52Z

1

A function cannot be defined inside an "if" block. You can call it within an "if" block, but should not define.

Here's the working code.

function myfunction() {
$title = $_POST['title'];
$url = $_POST['url'];
$message = $_POST['message'];
echo "<br>" . $title . "<br >". $url . "<br />" . $message;
}

if(!empty($_POST['title']) && !empty($_POST['url']) && !empty($_POST['message']) )
{
    myfunction();
}

It's a good idea to use empty() with $_POST

answered Aug 15, 2015 at 0:12

Wild Widow

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Comments

aldrin27 · Accepted Answer · 2015-08-15 00:51:37Z

0

You can also use isset()

function myfunction() {
  $title = $_POST['title'];
  $url = $_POST['url'];
  $message = $_POST['message'];

  echo '<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><head><title>Title WEB</title><meta http-equiv="content-type" content="text/html;charset=utf-8" />';
  echo '<style> body { width: 100%; margin: 0; padding: 0; } </style></head><body>';
  echo "<br />" . $title . "<br /><br />" . $url . "<br /><br />" . $message;
  echo "</body></html>";
}

if(isset($_POST['title'] && $_POST['url'] && $_POST['message'])) {
  myfunction();
}

edited Aug 15, 2015 at 0:51

answered Aug 15, 2015 at 0:35

aldrin27

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