Issue with using regular expressions

Question

I'm attempting to run the following bit of code in python.

import re
text = 'Hello 16 Hello 22 Hello 81 Hello 50'
sum = 0
for m in re.finditer('Hello', text):
  print('found', m.start(), m.end())
  a = m.end()
  b = m.end()+3
  print (text[a:b])
  block = str(text[a:b])
  sum += block
  print (sum)

I am continually getting this error:

TypeError: unsupported operand type(s) for +=: 'int' and 'str'

All I want to do is have my code parse through the text and add together specified numbers contained in it.

Does anyone know what I'm doing wrong?

Thanks

you need to cast the matched block into an int before summing. — ch3ka
– ch3ka, Commented Aug 15, 2015 at 14:51
@user1929959 how will that help?! Augmented assignment is (generally) the same as the standard equivalent; sum = sum + block will have exactly the same error as sum += block. — jonrsharpe
– jonrsharpe, Commented Aug 15, 2015 at 14:52

Assem · Accepted Answer · 2015-08-15 14:53:08Z

2

You can't add an str to an int in sum += block. You should convert block first to int. Change line:

 block = str(text[a:b])

to:

 block = int(text[a:b])

answered Aug 15, 2015 at 14:53

Assem

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1 Comment

QM-Hacker Over a year ago

Thanks! Changing to int fixed it.

Nhor · Accepted Answer · 2015-08-15 14:52:20Z

0

Your sum is an int and you are trying to add a str to it. I think you mean

  block = int(text[a:b])

answered Aug 15, 2015 at 14:52

Nhor

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Comments

pythad · Accepted Answer · 2015-08-15 14:55:29Z

0

Maybe I've understood something wrong but to find some numbers in a string you can just use r'\d+'. This code will sum all numbers in a string:

sum(int(i) for i  in re.findall(r'\d+', 'Hello, 7, 89 Vlad'))

answered Aug 15, 2015 at 14:55

pythad

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