Can a javascript closure function act as a callback?

Question

I registered a callback function(abc) for a forEach call. The function abc is defined as a closure and it seems it doesn't get called. I would really appreciate to know more about this.

Code:

function xyz(array)
{
  // do something

  function abc(value,index,origin_array){
    // do something
  }

  array.forEach(abc);

  //other stuff
}

You should give a complete, runnable example that reproduces your problem. Currently, you don't call xyz (so we don't know what the value of array is). Other than that, your code looks perfectly fine, so it's not possible to give you an answer. — apsillers
– apsillers, Commented Aug 17, 2015 at 18:31
You need to add MCVE: How to create a Minimal, Complete, and Verifiable example — gfullam
– gfullam, Commented Aug 17, 2015 at 18:32

gfullam · Accepted Answer · 2015-08-17 20:55:58Z

1

A minimal, complete, and verifiable example

This works in modern browsers, but for what it's worth, array.forEach is not compatible with IE8 and older, if perhaps that is where you are testing this.

For legacy browser compatibility, use a standard for loop instead.

var numbers = [1, 2, 3];

function xyz(array) {
  console.log(array);
  
  function abc(value, index, origin_array){
    console.log(value);
  }

  array.forEach(abc);
}

xyz(numbers);

<p>Open your development console.</p>

answered Aug 17, 2015 at 20:55

gfullam

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