Deserialize Xml C# with XmlSerializer

Question

<response id=\"f57127c5-c7c5-4e31-bf60-a4b47ddb95c6\">
   <error-code>0</error-code>
   <error-message></error-message>
   <result xsi:type=\"entityWrapper\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\">
        <elements>
            <element xsi:type=\"decisionImpl\">
                <cityId>0</cityId>
                <createdDate>2015-08-21T14:58:46.570+07:00</createdDate>    
                <createdUser>5</createdUser
                <effectiveDate>2015-07-05T17:03:44.947+07:00</effectiveDate>
                <enterpriseId>5</enterpriseId>
                <equipmentSystem>K</equipmentSystem>
                <id xsi:type=\"xs:long\" xmlns:xs=\"http://www.w3.org/2001/XMLSchema\">8</id><invoiceType>1;</invoiceType>
                <modifiedDate>2015-08-21T14:58:47.045+07:00</modifiedDate>
                <modifiedUser>5</modifiedUser><number>HC889</number>
                <proponentName>Quang</proponentName>
                <status>0</status>
            </element>
        </elements>
    </result>
</response>

My Xml like that

public class Decision
    {
        [XmlAttribute(Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
        public String type = Constants.Type.DECISION;
        [XmlElement(ElementName = "id")]
        public long id { get; set; }
        [XmlElement(ElementName = "enterpriseId")]
        public long enterpriseId { get; set; }
        [XmlElement(ElementName = "number")]
        public String number { get; set; }
        [XmlElement(ElementName = "proponentName")]
        public String proponentName { get; set; }
        [XmlElement(ElementName = "equipmentSystem")]
        public String equipmentSystem { get; set; }
        [XmlElement(ElementName = "softwareApplication")]
        public String softwareApplication { get; set; }
        [XmlElement(ElementName = "processCreator")]
        public String processCreator { get; set; }
        [XmlElement(ElementName = "responsible")]
        public String responsible { get; set; }
        [XmlElement(ElementName = "effectiveDate")]
        public DateTime effectiveDate { get; set; }
        [XmlElement(ElementName = "cityId")]
        public long cityId { get; set; }
        [XmlElement(ElementName = "recipient")]
        public String recipient { get; set; }
        [XmlElement(ElementName = "invoiceType")]
        public String invoiceType { get; set; }
        [XmlElement(ElementName = "status")]
        public int status { get; set; }
        [XmlElement(ElementName = "createdDate")]
        public DateTime createdDate { get; set; }
        [XmlElement(ElementName = "modifiedDate")]
        public DateTime modifiedDate { get; set; }
        [XmlElement(ElementName = "createdUser")]
        public String createdUser { get; set; }
        [XmlElement(ElementName = "modifiedUser")]
        public String modifiedUser { get; set; }
    }

    [Serializable]
    [XmlRoot(ElementName = "response")]
    public class MessageResponseWrapperList<T>
    {
        [XmlAttribute(AttributeName = "id")]
        public String id { get; set; }
        [XmlElement(ElementName = "error-code")]
        public String errorCode { get; set; }
        [XmlElement(ElementName = "error-message")]
        public String errorMessage { get; set; }
        [XmlElement(ElementName = "result")]
        public DataWrapper<T> wrapper { get; set; }

    }

    [Serializable]
    public class DataWrapper<T>
    {
        [XmlAttribute(Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
        public String type = "entityWrapper";
        [XmlArray(ElementName = "elements")]
        [XmlArrayItem(ElementName = "element")]
        public List<T> result { get; set; }
    }

My function, I want to deserialize to MessageResponseWrapperList with List

public static MessageResponseWrapperList<T> fromXmlWrapper<T>(String xml)
        {
            StringReader reader = new StringReader(xml);
            XmlSerializer serializer = new XmlSerializer(typeof(MessageResponseWrapperList<T>));
            MessageResponseWrapperList<T> t = (MessageResponseWrapperList<T>)serializer.Deserialize(reader);
            return t;
        }

But I get error

An unhandled exception of type 'System.InvalidOperationException' occurred in System.Xml.dll

Additional information: There is an error in XML document (1, 165).

tdgtyugdyugdrugdr · Accepted Answer · 2015-08-21 10:55:41Z

3

It's true that there's an error in XML document

Change

<createdUser>5</createdUser

to

<createdUser>5</createdUser>

Close bracket.

answered Aug 21, 2015 at 10:55

tdgtyugdyugdrugdr

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1 Comment

Kull Over a year ago

that's not true because xml not error like you said. I check again error again

jdweng · Accepted Answer · 2015-08-21 11:03:49Z

1

A double quote doesn't need a backslash in an xml file. Below is your xml with all errors removed

<?xml version="1.0" encoding="utf-8" ?>
<response id="f57127c5-c7c5-4e31-bf60-a4b47ddb95c6">
  <error-code>0</error-code>
  <error-message></error-message>
  <result xsi:type="entityWrapper" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <elements>
      <element xsi:type="decisionImpl">
        <cityId>0</cityId>
        <createdDate>2015-08-21T14:58:46.570+07:00</createdDate>
        <createdUser>5</createdUser>
        <effectiveDate>2015-07-05T17:03:44.947+07:00</effectiveDate>
        <enterpriseId>5</enterpriseId>
        <equipmentSystem>K</equipmentSystem>
        <id xsi:type="xs:long" xmlns:xs="http://www.w3.org/2001/XMLSchema">8</id>
        <invoiceType>1;</invoiceType>
        <modifiedDate>2015-08-21T14:58:47.045+07:00</modifiedDate>
        <modifiedUser>5</modifiedUser>
        <number>HC889</number>
        <proponentName>Quang</proponentName>
        <status>0</status>
      </element>
    </elements>
  </result>
</response>

answered Aug 21, 2015 at 11:03

jdweng

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6 Comments

Kull Over a year ago

i don't know what's you mean?

jdweng Over a year ago

when you have as double quote inside a sting you need to use a backslash like "There is a double quote at end of tis string\"". Note the two double quotes at the end together. You do not need to do this in an XML document. So an attribute looks like this version="1.0", not version=\"1.0\".

Kull Over a year ago

oh no! that is escape space character in String not "double quote"

jdweng Over a year ago

I know. There are a number of places in your original XML where it is obviously WRONG!!! Attributes should not have the escape character.

Kull Over a year ago

when i type String sample = "<id name=\"abc\">"; i need that! so you think wrong my way :)

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