6

I can't figure out why Django is unable to find the requested URL in my application.

Here is the error code I get:

 Using the URLconf defined in littlelogsms.urls, Django tried these URL patterns, in this order:
^admin/
^$
The current URL, success/, didn't match any of these.

Here is my sms.urls.py file:

from django.conf.urls import url

from sms import views

urlpatterns = [
    url(r'^success/$', views.success, name='success'),
    url(r'^$', views.index, name='index')
]

Here is the application urls.py file:

from django.conf.urls import include, url
from django.contrib import admin


urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^$', include('sms.urls')),
]

I can't find the mistake I'm making. Any ideas?

0

2 Answers 2

10

This problem is the dollar sign in this url pattern.

url(r'^$', include('sms.urls')),

The caret ^ matches the beginning of the string, and the dollar $ matches the end if the string, so ^$ only matches the index URL /.

You should remove the dollar and change it to:

url(r'^', include('sms.urls')),
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1 Comment

thank you!! knew it was something very simple that I wasn't getting :)
1

you should try with the base url,like

Here is the application urls.py file:

from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^sms', include('sms.urls')),   # 'sms' is your defined name
]

Here is my sms.urls.py file:

from django.conf.urls import url

from sms import views

urlpatterns = [
    url(r'^success/$', views.success, name='success'),
    url(r'^$', views.index, name='index')
]

you should try accessing your url's like in your views as

sms/ //for accessing tht index function in view sms/success //for accessing the success function in view

or you can use the labels in the form's action tag in the templates to call the urls,

{% url 'sms:index or success' %} //index,success is the name space given in the sms.urls

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