Consider the following file\directory structure:
project\
| django_project\
| | __init__.py
| | django_app1\
| | | __init__.py
| | | utils\
| | | | __init__.py
| | | | bar1.py
| | | | ...
| | | ...
| | django_app2\
| | | __init__.py
| | | bar2.py
| | | ...
| | ...
| scripts\
| | __init__.py
| | foo.py
| | ...
How should I use sys.path.append in foo.py so that I could use bar1.py and bar2.py?
How would the import look like?
Using relative paths would be much more desirable for portability reasons.
At the top of your foo.py script add the following:
import os, sys
PROJECT_ROOT = os.path.join(os.path.realpath(os.path.dirname(__file__)), os.pardir)
sys.path.append(PROJECT_ROOT)
# Now you can import from the django_project package
from django_project.django_app1.utils import bar1
from django_project.django_app2 import bar2
import sys
sys.path.append('/absolute/whatever/project/django_project/django_app1')
sys.path.append('/absolute/whatever/project/django_project/django_app2')
Though you need to evaluate whether you want to have both in your path -- in case there are competing module names in both. It might make sense to only have up to django_project in your path, and call django_app1/bar1.py when you need it and import django_app2.bar2.whatever when you need it.
