Regex in R: replace only part of a pattern

Question

s <- "YXABCDXABCDYX"

I want to use a regular expression to return ABCDABCD, i.e. 4 characters on each side of central "X" but not including the "X". Note that "X" is always in the center with 6 letters on each side.

I can find the central pattern with e.g. "[A-Z]{4}X[A-Z]{4}", but can I somehow let the return be the first and third group in "([A-Z]{4})(X)([A-Z]{4})"?

you almost got it gsub('.*([A-Z]{4})(X)([A-Z]{4}).*', '\\1\\3', s) — rawr
– rawr, Commented Oct 11, 2015 at 14:30
Yeah, I was trying something with replacement="\\1" (etc) but I didnt quite understand it. You can put it as answer. — user3375672
– user3375672, Commented Oct 11, 2015 at 14:36

rawr · Accepted Answer · 2015-10-11 14:37:15Z

12

Your regex "([A-Z]{4})(X)([A-Z]{4})" won't match your string since you have characters before the first capture group ([A-Z]{4}), so you can add .* to match any character (.) 0 or more times (*) until your first capture group.

You can reference the groups in gsub, for example, using \\n where n is the nth capture group

s <- "YXABCDXABCDYX"

gsub('.*([A-Z]{4})(X)([A-Z]{4}).*', '\\1\\3', s)
# [1] "ABCDABCD"

which is basically matching the entire string and replacing it with whatever was captured in groups 1 and 3 and pasting that together.

Another way would be to use (?i) which is case-insensitive matching along with [a-z] or \\w

gsub('(?i).*(\\w{4})(x)(\\w{4}).*', '\\1\\3', s)
# [1] "ABCDABCD"

Or gsub('.*(.{4})X(.{4}).*', '\\1\\2', s) if you like dots

answered Oct 11, 2015 at 14:37

rawr

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1 Comment

hwnd Over a year ago

Or gsub('(.{4})X(.{4})|.', '\\1\\2', s)

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