or u want class and u want to use for creating api lib then just copy paste this class ..this is for c# but almost similer syntax for java ...
with this u can access any api or url or also used to pass json file to server ..
using Newtonsoft.Json.Linq;
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Net;
using System.Text;
using System.Threading.Tasks;
namespace ExternalAPIs_SynapsePay.Helpers
{
class RESTHelpers
{
public dynamic APICalls(JObject jsonObject, string endpoints, string method)
{
HttpWebRequest httpRequest = (HttpWebRequest)HttprequestObject(endpoints, method);
using (var streamWriter = new StreamWriter(httpRequest.GetRequestStream()))
{
streamWriter.Write(jsonObject);
streamWriter.Flush();
streamWriter.Close();
}
var result = "";
HttpWebResponse httpResponse;
try
{
httpResponse = (HttpWebResponse)httpRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
result = streamReader.ReadToEnd();
}
}
catch (WebException e)
{
Console.WriteLine("This program is expected to throw WebException on successful run." +
"\n\nException Message :" + e.Message);
if (e.Status == WebExceptionStatus.ProtocolError)
{
Console.WriteLine("Status Code : {0}", ((HttpWebResponse)e.Response).StatusCode);
Console.WriteLine("Status Description : {0}", ((HttpWebResponse)e.Response).StatusDescription);
using (Stream data = e.Response.GetResponseStream())
using (var reader = new StreamReader(data))
{
string text = reader.ReadToEnd();
Console.WriteLine(text);
}
}
}
catch (Exception e)
{
Console.WriteLine(e.Message);
}
return result;
//return "Success";
//not sure what to return
//here i have to add sql server code to enter into database
}
public HttpWebRequest HttprequestObject(string endpoints, string method)
{
string url = Setting.API_TEST_VALUE + endpoints;
var httpWebRequest = (HttpWebRequest)WebRequest.Create(url);
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = method;
return httpWebRequest;
}
/// <summary>
/// This method is useful when you have to pass JSON as string not as object... This is basically a constructor..
/// Even if u pass json object it will accept, so no need to worry about that.
/// </summary>
/// <param name="ljson"></param>
/// <param name="endpoints"></param>
/// <param name="method"></param>
/// <returns></returns>
public dynamic APICalls(string jsonString, string endpoints, string method)
{
HttpWebRequest httpRequest = (HttpWebRequest)HttprequestObject(endpoints, method);
using (var streamWriter = new StreamWriter(httpRequest.GetRequestStream()))
{
streamWriter.Write(jsonString);
streamWriter.Flush();
streamWriter.Close();
}
var result = "";
HttpWebResponse httpResponse;
try
{
httpResponse = (HttpWebResponse)httpRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
result = streamReader.ReadToEnd();
}
}
catch (WebException e)
{
Console.WriteLine("This program is expected to throw WebException on successful run." +
"\n\nException Message :" + e.Message);
if (e.Status == WebExceptionStatus.ProtocolError)
{
Console.WriteLine("Status Code : {0}", ((HttpWebResponse)e.Response).StatusCode);
Console.WriteLine("Status Description : {0}", ((HttpWebResponse)e.Response).StatusDescription);
using (Stream data = e.Response.GetResponseStream())
using (var reader = new StreamReader(data))
{
string text = reader.ReadToEnd();
Console.WriteLine(text);
result = text;
}
}
}
catch (Exception e)
{
Console.WriteLine(e.Message);
}
return result;
//return "Success";
//not sure what to return
//here i have to add sql server code to enter into database
}
public void HttlpResponseObject(HttpWebRequest httpResponse)
{
var response = (HttpWebResponse)httpResponse.GetResponse();
using (var streamReader = new StreamReader(response.GetResponseStream()))
{
var result = streamReader.ReadToEnd();
}
//entry into databse can be done from here
//or it should return some value
}
}
}