jQuery and ajaxSend not firing

Question

I set the global ajaxSend callback as below in my $(document).ready function.

 // global AJAX methods
 $(document).ajaxSend(function(e, xhr, settings) {
  alert('here');
    });

However, I am never getting here even though I have several $.ajax() calls that run successfully after the document has loaded and on demand. Yet, here appears when I calling $.post.

Do global methods not call for $.ajax requests? I have not modified the global param, so they should.

I am fine using the beforeSend, but I need access to the url and other request data.

Any ideas would be appreciated as I have yet to find any gotchas from the docs.

If you use firebug, try turn it off - there is bug in some of the latest version, which prevent from firing these events. — yedpodtrzitko
– yedpodtrzitko, Commented Jul 23, 2010 at 15:45

Community · Accepted Answer · 2017-05-23 11:48:28Z

0

Are you using IE by the way? If so it caches ajax calls which are not posts.

see this link: jQuery AJAX request failing in IE

edited May 23, 2017 at 11:48

CommunityBot

11 silver badge

answered Jul 23, 2010 at 15:51

Richard

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Comments

Sirber · Accepted Answer · 2010-07-23 17:53:07Z

-2

since it's a callback it doesn't need to be in $(document).ready. It can be a standard function.

set your callback function in your $.ajax calls and everything will be fine.

[edit]

function ajaxSend(data)
{
alert('hello');
}

$.ajax({url: [url],
            type: 'POST',
            cache: false,
            data: oData,
            success: ajaxSend});

keeping it easy.. :)

edited Jul 23, 2010 at 17:53

answered Jul 23, 2010 at 15:45

Sirber

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6 Comments

Jason McCreary Over a year ago

Please elaborate or provide a code sample. Your suggestion is unclear.

Jason McCreary Over a year ago

Thanks for the elaboration. Please note that ajaxSend is a global callback method. Your recent post could be misleading. However, moving $(document).ajaxSend(...) outside $(document).ready per your original suggestion resolved the problem. Rookie mistake.

Sirber Over a year ago

added some code. I hope I understood the OP's question right.

Sirber Over a year ago

@Jason: api.jquery.com/ajaxSend you are right, sorry I thought it was a handmade function.

locrizak Over a year ago

@Jason McCreary You should consider putting that comment as an answer because it is correct. This answer is not correct at all. Thanks!

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