Ruby-Regular expression to find index

Question

I want to fetch the value 10 from video[10]. How to do this using regular expression? I have tried : /video\[(.*?)\]/. This did not work.

How did it not work? It works fine for me (e.g. /video\[(.*?)\]/.match("video[10]")[1] gives "10"). — matt
– matt, Commented Nov 19, 2015 at 16:12

Long Nguyen · Accepted Answer · 2015-11-19 12:00:11Z

1

It should be /video\[(.*)\]/.

/video\[(.*)\]/.match "video[10]"
#=> #<MatchData "video[10]" 1:"10">

answered Nov 19, 2015 at 12:00

Long Nguyen

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1 Comment

Cary Swoveland Over a year ago

You need to make .* non-greedy: /video\[(.*)\]/.match "video[10]]]]" #=> #<MatchData "video[10]]]]" 1:[10]]]">.

Cary Swoveland · Accepted Answer · 2015-11-19 14:49:41Z

0

r = /
    \b      # match a word break
    video\[ # match string
    (\d+)   # match >= 1 digits in capture group 1
    \]      # match char
    /x      # extended/free-spacing mode

"Martha, where did you put video[10]?"[r,1]
  #=> "10"

edited Nov 19, 2015 at 14:49

answered Nov 19, 2015 at 14:42

Cary Swoveland

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