Python: Alternate way to covert from base64 string to opencv

Question

I'm trying to convert this string in base64 (http://pastebin.com/uz4ta0RL) to something usable by OpenCV. Currently I am using this code (img_temp is the string) to use the OpenCV functions by converting it to a temp image(imagetosave.jpg) then loading the temp image with cv2.imread.

    fh = open('imagetosave.jpg','wb')
    fh.write(img_temp.decode('base64'))
    fh.close()

    img = cv2.imread('imagetosave.jpg',-1)

Though this method works, I would like to be able to use the OpenCV functions without using a temp image. Help would be much appreciated, thanks!

stackoverflow.com/a/33522724/5008845

Miki
– Miki

2015-12-01 00:01:33 +00:00
Commented Dec 1, 2015 at 0:01 — Miki
– Miki, Commented Dec 1, 2015 at 0:01
thanks, i thought i had already tried that but i guess not!

user3547372
– user3547372

2015-12-01 01:00:11 +00:00
Commented Dec 1, 2015 at 1:00 — user3547372
– user3547372, Commented Dec 1, 2015 at 1:00

Nikita Sapozhnikov · Accepted Answer · 2015-11-30 23:11:36Z

0

To convert string from base64 to normal you can use

import base64
base64.b64decode("TGlrZSB0aGF0Cg==")

but it itsn't unclear if is what you need.

answered Nov 30, 2015 at 23:11

Nikita Sapozhnikov

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user3547372 Over a year ago

So I'd like to be able to use the string from base64 to a format useable by OpenCV without having to write over imagetosave.jpg since its acting as a temporary image.

Sajjan Singh · Accepted Answer · 2015-11-30 23:17:33Z

0

You can convert your decoded string to a list of integers, which you can then pass to the imdecode function:

img_array = map(int, img_temp.decode('base64'))
img = cv2.imdecode(img_array, -1)

answered Nov 30, 2015 at 23:17

Sajjan Singh

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1 Comment

user3547372 Over a year ago

I'm getting: invalid literal for int() with base 10

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