Deleting pattern from file using vim

Question

I'm trying to delete pattern from a file.

Edge[15] = 415 
Edge[16] = 65 
Edge[17] = 835 
Edge[18] = 951 
Edge[19] = 999 
Edge[20] = 887 ...

How to delete everything before Numbers i.e till = , i.e i want just numbers and then wants to join using ,.

[415,65,835,...]

Have you tried anything so far? By showing your attempts and describing what parts you are having difficulty with, we get a better understanding of your proficiency and can give a more precise answer. As it stands, it just looks like you've posted a requirement and want someone to write your code for you. — Ingo Karkat
– Ingo Karkat, Commented Dec 4, 2015 at 11:47
Oh forgot about the post ... I can search for .*= and replace it with = /=... i.e delete all things till = . and then do the same and replace it with empty. then add using regular expression at end of line , and then %j . I wanted was a one liner . If possible... — user2754673
– user2754673, Commented Dec 4, 2015 at 17:27

Ingo Karkat · Accepted Answer · 2015-12-04 19:41:51Z

2

Okay, so you're asked for a one-liner instead of the multiple steps you've given. There surely are many other ways, here's one:

:%s/.*=\s*\(\d\+\)\n/\1, / | normal! $xr]^OI[

This does the removal of the stuff before = and the joining of lines both with :substitute (adapt the :% range to suit your needs), by capturing only the number. I then use normal mode commands to get rid of the trailing comma and add the square brackets. (Type ^O as Ctrl-V Ctrl-O; Ctrl-Q CTRL-O on Windows.) If you have the surround.vim plugin, this could be further simplified. One could also use a second :.substitute to achieve the same.

Actually, I probably would have used visual blockwise mode, a special J mapping, and normal mode to achieve this.

answered Dec 4, 2015 at 19:41

Ingo Karkat

174k16 gold badges265 silver badges341 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

user2754673 Over a year ago

oh.. Need some time to digest it. Thanks.

Ingo Karkat Over a year ago

Don't forget the excellent built-in :help; you'll learn tons from it!

user2754673 Over a year ago

Okay. Have just started to use vim hence little slow in catching. But surely will become dangerous in few weeks,

Alan Gómez · Accepted Answer · 2024-02-04 17:12:52Z

0

You can use two regex

:%s/.*\( \d\+\).*\n/\1,/g

:%s/^ \(.*\),.\{-}$/[\1]

Output:

[415, 65, 835, 951, 999, 887]

answered Feb 4, 2024 at 17:12

Alan Gómez

3881 gold badge4 silver badges11 bronze badges

Collectives™ on Stack Overflow

Deleting pattern from file using vim

2 Answers 2

3 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

3 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related