4

I'm using an Oracle DB and I'm trying to fetch data from its tables using PHP. One of the tables contains a date column which behaves strange to me.

When I open the table in my DB client (I'm using Navicat Lite) I see dates like "2007-11-29 10:15:42" but when I retrieve them with PHP and display the date it says "29-NOV-07". I use a simple SQL query and standard PHP functions (oci_parse, oci_execute, oci_fetch_array).

Why is the value from the DB converted to this (useless) format? How can I get the date just like it is stored in the DB? Thanks for your tips!

1 Answer 1

8

Oracle DATE datatype is a point in time, it has no format attached. When you transform a date to a string (to display if for example), the format applied to the date will be dependent upon your session parameters (implicit conversion). From what I remember of PHP, the retrieval functions will convert the date to a string automatically, using the NLS_DATE_FORMAT session parameter.

Either:

  • change the NLS_DATE_FORMAT beforehand with:

    ALTER SESSION SET NLS_DATE_FORMAT='yyyy-mm-dd hh24:mi:ss'
    
  • or, if you want to specify another format in your query, you should explicitely ask for it:

     SELECT to_char(my_date, 'yyyy-mm-dd hh24:mi:ss') ...
    

Update

Thanks to ThinkJet for the link to the PHP documentation:

DATE columns are returned as strings formatted to the current date format. The default format can be changed with Oracle environment variables such as NLS_LANG or by a previously executed ALTER SESSION SET NLS_DATE_FORMAT command.

Sign up to request clarification or add additional context in comments.

1 Comment

+1 Look at return values description here: php.net/manual/en/function.oci-fetch-array.php

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.