Using For loop to call a function

Question

I need some help with this function to finish my project.

3 variables:

$cityName1 = "New York";
$cityName2 = "Madrid";
$cityName3 = "Paris";

The function:

function cityNameFunction($cityName) {
    $city_name = $cityName;
    return $city_name;
}

Calling the function:

$cityName = array();
for($x = 1; $x <= 3; $x++) {
    $cityName[$x] = ${'cityName'.$x};
}
$cityName1 = cityNameFunction($cityName1);
$cityName2 = cityNameFunction($cityName2);
$cityName3 = cityNameFunction($cityName3);

What do I have to do if I have 2000 cities?

Thanks for any help

This is just a example for my real code, otherwise you won't understand my language. I just want to return the name of every city. — Shamss Zaidan
– Shamss Zaidan, Commented Dec 27, 2015 at 19:12
Where do you have 2000 cities. What I mean is, in what data structure do you have these city names? — RiggsFolly
– RiggsFolly, Commented Dec 27, 2015 at 19:15

Nick · Accepted Answer · 2015-12-27 19:14:34Z

1

Strange example, but you may write something like this

$cityName = array();
for ($x = 1; $x <= 3; $x++) {
    $cityName[$x] = ${'cityName'.$x};
    ${'cityName'.$x} = cityNameFunction(${'cityName'.$x});
}

answered Dec 27, 2015 at 19:14

Nick

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2 Comments

Shamss Zaidan Over a year ago

Thank you mnv. I will try it.

Shamss Zaidan Over a year ago

Your code works perfect of my example. Now I will try it on my real code. You will hear it from me:)

user5613751 · Accepted Answer · 2015-12-27 19:12:38Z

0

An example of Itterating over a PHP Function at work:

$new = array(1,2,3,4);
    for($i=0;$i<=3;$i++)
    {
        $val = $new[$i];
        if(!function_exists('myfunction'))
        {
            function myfunction($value) {
                //Do something
            }
        }
        echo $val;
    }

answered Dec 27, 2015 at 19:12

user5613751

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