How to initialize variable in Scala?

Question

I have this sample code:

val someCondition = true
case class SampleClass (source: String)

val sample: SampleClass

if (someCondition)
  sample = new SampleClass("Some String")
else
  sample = new SampleClass("Other String")

I want to define a val argument and initialize it based on some condition. but I can't figure out how to do that. also, if I change it to var I still can't.

It's idiomatic to treat if-else's in Scala as expressions, not statements. — Kevin Meredith
– Kevin Meredith, Commented Dec 30, 2015 at 21:04

MirMasej · Accepted Answer · 2015-12-30 13:00:10Z

6

In Scala if is an expression, which means it evaluates to some value, hence you can do the following:

val sample = if (someCondition) new SampleClass("Some String")
             else new SampleClass("Other String")

answered Dec 30, 2015 at 13:00

MirMasej

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Comments

cchantep · Accepted Answer · 2015-12-30 12:59:26Z

3

You can do as follows.

val sample: SampleClass = {
  if (someCondition) new SampleClass("Some String")
  else new SampleClass("Other String")
}

answered Dec 30, 2015 at 12:59

cchantep

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