setting up variables in alias is not working

Question

I want my alias to pick up variables that I pass in commandLine:

For example, startdocker 004 should execute the following

docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar:004

(004 is the tag I am passing in commandLine).

I tried the following in my .bashrc (sourced after the change).

alias startdocker='function dockerStartTag(){ echo "docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar: $1";};dockerStartTag'

when I run startdocker 004, It is not picking up 004. It is empty and hence defaults to "latest" by docker.

what is the correct way to do it? what am I doing wrong?

Thanks

EDIT

I don't want to echo but execute the command.

The correct answer is provided below

Possible duplicate of Make bash alias that takes parameter?

Benjamin W.
– Benjamin W.

2016-01-08 20:40:05 +00:00
Commented Jan 8, 2016 at 20:40 — Benjamin W.
– Benjamin W., Commented Jan 8, 2016 at 20:40

chrisaycock · Accepted Answer · 2016-01-08 19:39:01Z

2

There's no reason to put a function inside an alias. Just do

function startdocker(){ echo "docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar: $1"; }

This now works on my system:

$ startdocker 004
docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar: 004

And to actually run it, we just need:

function startdocker(){ docker run -d -t -p 8080:8080 -v /var/source:/source -P mydockerregistry:5000/foo/bar: $1; }

edited Jan 8, 2016 at 19:39

answered Jan 8, 2016 at 19:25

chrisaycock

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4 Comments

brain storm Over a year ago

oh may be I did not express correctly. I want that command to be executed. not printed on console

brain storm Over a year ago

I tried that. it does not work. I get No such file or directory.

brain storm Over a year ago

I also tried replacing idouble quotes with uptick `, so it can be executed. but it does not

chrisaycock Over a year ago

@brainstorm Don't put double quote or backticks or anything else in the function. It should be function startdocker(){ docker run -d ... $1; }

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