Java calculator debugging

Question

I am learning Java by debugging programs from various tutorials. At a moment I am fixing this calculator: http://www.dreamincode.net/forums/topic/321933-creating-a-calculator-using-jframe/
If you press "1/1" it displays "1.0" instead of "1". I am leaning towards

if (abs(result-round(result)) < 0.000000001){(int)(result)}

What would be an appropriate way to fix this glitch? Thank you in advance,

(int)(result) is meaningless. Do you mean result=(int)(result);? — MikeCAT
– MikeCAT, Commented Mar 18, 2016 at 2:33
Yes, I mean result=(int)(result);. Is there a better way to achieve this? I am trying to learn good coding practices. — Stepan
– Stepan, Commented Mar 18, 2016 at 2:37
@StepanLenevich if you do (int)(result); you don't get 1.5 for 3/2 — Madhawa Priyashantha
– Madhawa Priyashantha, Commented Mar 18, 2016 at 2:38
That is why I am checking for if (abs(result-round(result)) < 0.000000001) — Stepan
– Stepan, Commented Mar 18, 2016 at 2:39

Trey50Daniel · Accepted Answer · 2016-03-18 03:01:24Z

1

I think you are close to what you want, but this code is probably the more correct way to do it:

if (abs(result-round(result)) < 0.000000001){(int)Math.round(result);}

answered Mar 18, 2016 at 3:01

Trey50Daniel

1793 silver badges14 bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1