how to Add 1 year to startdate to get the end date in javascript

Question

want a output like below

if Start Date is "01-03-2016" the End date should be "28-02-2017" if Start Date is "10-04-2016" the End date should be "09-04-2017"

I tried below code

if (dat <= 31 && dat >= 1 && month <= 12 && month >= 1) {

            var expiryDate = new Date(n1, month - 1, dat);

            expiryDate.setFullYear(expiryDate.getFullYear() + 1);
            var day = ('0' + expiryDate.getDate()).slice(-2);
            var month1 = ('0' + (expiryDate.getMonth() + 1)).slice(-2);
            var year = expiryDate.getFullYear();
            var month = getMonthName(month1);

            var wholeenddate = day + "-" + month + "-" + year;

but it's not produce desired output.Please Help to solve it.

If i add 365 days then in case if my date is "01-03-2016" then it will give end date "01-03-2017" — piyush
– piyush, Commented Mar 22, 2016 at 5:06

gurvinder372 · Accepted Answer · 2016-03-22 05:11:11Z

4

Add 364 days to your date

For example

var d = new Date("2016-03-01");
d.setDate(d.getDate()+364); //outputs 28-02-2017

and

var d = new Date("2016-04-10");
d.setDate(d.getDate()+364); //outputs 09-04-2017

or Just add 1 year and sub 1 day.

d.setFullYear(d.getFullYear() + 1);
d.setDate(d.getDate()-1);

Now it will match your output just the same even for leap year :)

Demo

var d = new Date("2016-03-01");
d.setFullYear(d.getFullYear() + 1);
d.setDate(d.getDate()-1);
document.body.innerHTML += d.toString();

document.body.innerHTML += "<br>";


d = new Date("2016-04-10");
d.setFullYear(d.getFullYear() + 1);
d.setDate(d.getDate()-1);
document.body.innerHTML += d.toString();

edited Mar 22, 2016 at 5:11

answered Mar 22, 2016 at 5:06

gurvinder372

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5 Comments

epascarello Over a year ago

What happens in a leap year? ;)

gurvinder372 Over a year ago

@piyush what should be the output in case of 2016-01-01

piyush Over a year ago

output should be 2016-12-31

gurvinder372 Over a year ago

@piyush check the updated code at the end, it gives the output you are looking for

piyush Over a year ago

how can i do it same in php?

Tom · Accepted Answer · 2016-03-22 05:20:37Z

2

There's a convenient library to help with this sort of thing - moment.js (14k zipped).

var startDate = moment('01-03-2016', 'DD-MM-YYYY');
console.log(startDate.format('DD-MM-YYYY'));
var endDate = startDate.clone();
endDate.add(1, 'years').subtract('1', 'days');
console.log(endDate.format('DD-MM-YYYY'));

answered Mar 22, 2016 at 5:20

Tom

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Comments

SuperNova · Accepted Answer · 2016-03-22 05:47:23Z

0

3 ways to do this.

 // Add hours
 var today = new Date();
 today.setHours(today.getHours()+24*364);

 // Add days
 var nextyearDate = new Date();
 nextyearDate.setDate(today.getDate()+364);

 // More reliable way : Add year & subtract a day.. Hope this works...! Works for 01/01/2016
 var nextDate = new Date();
 nextDate.setYear(nextDate.getFullYear()+1);
 nextDate.setDate(nextDate.getDate()-1);

edited Mar 22, 2016 at 5:47

answered Mar 22, 2016 at 5:13

SuperNova

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1 Comment

SuperNova Over a year ago

@epascarello.. thanks for noticing this. I have edited.. hope the latest answer works

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