How can I print all children of a specific array that I detect via URL parameter?

Question

This is my array:

array(1) {
  ["farm"]=>
  array(1) {
    ["animals"]=>
    array(1) {
      [horses]=>
      array(4) {
        ["fred"]=>
        string(4) "fred"
        ["sam"]=>
        string(4) "sam"
        ["alan"]=>
        string(4) "alan"
        ["john"]=>
        string(4) "john"
      }
    }
  }
}

And this is my URL

mypage.php?id=2&dir=animals

I would like to print the children of my URL parameter dir(In this case:animals)

This is the way I try to do it:

 foreach($array as $sub) {
        if ($_GET['dir'] == $sub){
        $result = array_merge($result, $sub);
        echo $result;
        }
}

My result: An empty page.

The result I wish: horses

I found out that I need to write foreach($array as $sub => $key) { but then my result is farm — peace_love
– peace_love, Commented Apr 5, 2016 at 15:14
If you want to use key it's the other way. foreach($array as $key => $sub) {...} — Daniel Dudas
– Daniel Dudas, Commented Apr 5, 2016 at 15:15
@FrayneKonok If dir is animals, the result should be horses — peace_love
– peace_love, Commented Apr 5, 2016 at 15:18

Murad Hasan · Accepted Answer · 2016-04-05 16:09:07Z

1

Your array:

$arr = array("farm" => 
             array("animals"=>
                   array("horses" => 
                         array("fred" => "fred",
                               "sam" => "sam",
                               "alan" => "alan",
                               "john" => "john")
                        )
                  )
            );

Here we go, i make a recursive function for searching the value.

This function not work if you search for fred and their siblings.

$search = 'horses';
get_values($arr);

function get_values($arr){  
    global $search;
    foreach($arr as $key => $value){
        if($key == $search){
            if(is_array($value)){
                echo join(", ", array_keys($value));
            }           
            else{
                echo $value;
            }
        }else{
            get_values($value);
        }       
    }   
}

Output:

fred, sam, alan, john

edited Apr 5, 2016 at 16:09

answered Apr 5, 2016 at 16:02

Murad Hasan

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7 Comments

peace_love Over a year ago

One question, if I want to write instead of fred, sam, alan, john <li>fred</li><li>sam</li><li>alan<l/i><li>john</li>. How do I do that?

peace_love Over a year ago

I do not know if this is the best way:

if(is_array($value)){             echo "<li>";                 echo join("</li><li>",array_keys($value));                 echo "</li>";                 }

peace_love Over a year ago

I get some problems when I want to make a link:

if(is_array($value)){             echo "<a href='mypage.php?id=".$id."&dir=".value."'><li>";                 echo join("</li></a><a href='mypage.php?id=".$id."&dir=".value."'><li>",array_keys($value));                 echo "</li></a>";                 }

the value in the link is always printing the word Array instead of the for example fred. And do I have to write the links twice?

Murad Hasan Over a year ago

Let's see tomorrow. Now I am sleeping.

peace_love Over a year ago

Thank you very much, my problem is that I need as a result the same value inside the link of each like <li><a href="mypage.php?dir=fred">fred</a></li><li><a href="mypage.php?dir=sam">sam</a></li> I cannot get the second fred between it. But you helped me already enough, so I will make a new question for it :)

|

Daniel Dudas · Accepted Answer · 2016-04-05 15:15:13Z

0

Your $array has a farm key and that farm only contains your dir animals.

If everything is in farm you can do like this:

if(!empty($_GET['dir'])) {
  $result = array_merge($result, $array['form'][$_GET['dir']]
}
print_r($result);

I don't know what $result contains initially, but you can adapt if this is not the case or just echo $array['form'][$_GET['dir']] if you don't have multiple items in $result

edited Apr 5, 2016 at 15:15

answered Apr 5, 2016 at 15:14

Daniel Dudas

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5 Comments

Murad Hasan Over a year ago

what to do if the dir is horses.

peace_love Over a year ago

@Frayne Konok yes it is possible, that dir is horses, also that dir is farm

Daniel Dudas Over a year ago

From question is not clear if dir can be anything or just keys from farm. The solution from above is just for farm items. It needs to be adapted to check everywhere.

peace_love Over a year ago

@DanielDudas dir can be anything

peace_love Over a year ago

I tried to use your code, but I get an empty white page

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