Get total number of each unique value in an array?

Question

Okay, so I've got an array that has a ton of random numbers in it, like this...

$array = array(134, 12, 54, 134, 22, 22, 1, 9, 45, 45, 12, 134, 45, 134);

What I need to do, is find out what numbers are contained in my array, and if a number is duplicated in the array, I'd like to know how many times that number is found within the array. So taking the array that I listed above, I need the results to be something like this:

134: 4
12: 2
54: 1
22: 2
1: 1
9: 1
45: 3
etc.

Any bright ideas on how this might be accomplished?

Thanks!

Artefacto · Accepted Answer · 2010-09-05 03:13:47Z

8

See array_count_values.

<?php
print_r(array_count_values(
        array(134, 12, 54, 134, 22, 22, 1, 9, 45, 45, 12, 134, 45, 134)));

gives:

Array
(
    [134] => 4
    [12] => 2
    [54] => 1
    [22] => 2
    [1] => 1
    [9] => 1
    [45] => 3
)

answered Sep 5, 2010 at 3:13

Artefacto

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1 Comment

Russell Dias Over a year ago

And here I am writing a function to answer the authors question. Didn't know this function existed. Thanks!

BoltClock · Accepted Answer · 2010-09-05 03:14:03Z

2

Use array_count_values() to count the occurrences of each unique value:

$counts = array_count_values($array);
var_dump($counts);

Output:

array(7) {
  [134]=>
  int(4)
  [12]=>
  int(2)
  [54]=>
  int(1)
  [22]=>
  int(2)
  [1]=>
  int(1)
  [9]=>
  int(1)
  [45]=>
  int(3)
}

answered Sep 5, 2010 at 3:14

BoltClock

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Comments

ocodo · Accepted Answer · 2010-09-05 03:14:08Z

2

You can use the function:

array_count_values($array)

answered Sep 5, 2010 at 3:14

ocodo

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