Help with capturing with regexp

Question

I have this list:

foo chef.rb baz
bar cucumber.rb bar
baz gem.rb foo

I want to capture all the names without .rb.

My current regexp looks like this:

/([^\s](?:.)*?.(?:rb))/i

But it captures the .rb too.

How do I capture just the base name?

Thanks.

NullUserException · Accepted Answer · 2010-09-12 04:04:28Z

2

Use this regex instead:

/(\w*?)\.rb\s*.*/i

And your base-name will be in the 1st capture group.

See it on rubular.

edited Sep 12, 2010 at 4:04

answered Sep 12, 2010 at 3:49

NullUserException

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4 Comments

never_had_a_name Over a year ago

Hmm weird, it should work, I donno why it dropped the first letter in the basename: hef, ucumber, gem, it etc.

NullUserException Over a year ago

@ajsie It shouldn't (see link). Where's the rest of your code?

never_had_a_name Over a year ago

@NullUserException: Look at my update. I forgot to tell you there are letters before and after the filenames. Could you customize your regexp to that?

NullUserException Over a year ago

@ajsie Regex updated, though now I am not as confident on it. You might want to throw some test cases at it.

glenn jackman · Accepted Answer · 2010-09-12 12:13:39Z

0

This is a bit simpler: /(\S+).rb(?:$|\s)/

Any non-space chars followed by .rb followed by either the end of line or a space.

answered Sep 12, 2010 at 12:13

glenn jackman

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