WebServlet url-pattern ending by /jsfinspector

Question

I'd like to map a servlet for every url ending with "/jsfinspector". For example:

http://localhost/myapp/pages/somewhere/jsfinspector
http://localhost/myapp/jsfinspector

Is it possible to do that? In a very simple way, without declaring all possible url patterns in web.xml?

BalusC · Accepted Answer · 2016-05-03 12:51:45Z

1

The Servlet API doesn't support that.

Your best bet is creating a @WebFilter("/*") which forwards to @WebServlet("/jsfinspector") when the URL matches, as shown below:

if (request.getRequestURI().endsWith("/jsfinspector")) {
    request.getRequestDispatcher("/jsfinspector").forward(request, response);
} else {
    chain.doFilter(request, response);
}

You can if necessary extract the original request URI in servlet as below:

String originalRequestURI = (String) request.getAttribute(RequestDispachter.FORWARD_REQUEST_URI);

answered May 3, 2016 at 12:51

BalusC

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1 Comment

Rapster Over a year ago

Thank you BalusC! It helps a lot ;)

OttavioMonzione · Accepted Answer · 2016-05-03 12:50:03Z

0

You could think about creating a filter to intercept every request and eventually redirect the flow. https://docs.oracle.com/javaee/6/tutorial/doc/bnagb.html

answered May 3, 2016 at 12:50

OttavioMonzione

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