Foreach not working in php and Jquery

Question

I am trying to do a foreach loop in php and jquery for multiple select but all i am getting to echo out is Array.

html

<select multiple="multiple" class="select tagz" required>

php

if(!empty($_POST['tagz'])){
            $tag = $_POST['tagz']);

            foreach($tag as $tagz){
            echo $tagz;
            }

        }else{
            echo "Please select tags";
        }

Jquery

function serealizeSelects (select)
        {
            var array = [];
            select.each(function(){ array.push($(this).val()) });
            return array;
        }
        var tagz = serealizeSelects($(".tagz"));
$.post('upload.php', {tagz:tagz, title:title, category:category, description:description, price:price}, function(data){

            $('#confirm').html(data);

        });

Please tell me what i am doing wrong

Your select element is not named therefor $_POST['tagz'] is empty. — Wobbles
– Wobbles, Commented May 12, 2016 at 12:53
php and jquery (javascript) are two different worlds ... the php is running on your server ... the javascript is running on your browser .. — dsdsdsdsd
– dsdsdsdsd, Commented May 12, 2016 at 12:54
@Wobbles please let them check,i think you didn't specify $tag = $_POST['tagz']); to $tag = $_POST['tagz']; — Parth Chavda
– Parth Chavda, Commented May 12, 2016 at 13:08
if you think something is helpful but not clear explanation so you can edit my ans.it's my pleasure if you make me correct @Wobbles — Parth Chavda
– Parth Chavda, Commented May 12, 2016 at 13:13

George Pant · Accepted Answer · 2016-05-12 13:10:11Z

1

You are doing select.each(function(){ array.push($(this).val()) }); but select variable contains only the select element and each has no meaning.You need to use each in the options.So change your selector.

           var tagz = serealizeSelects($(".tagz option"));

or if you dont want to change the selector just use find to find all options inside your select

           select.find('option').each(function(){ array.push($(this).val()) })

Of course i cannot know where you define your other variables.If you have other problems too just show me your whole javascript code so I can help you more.

edited May 12, 2016 at 13:10

answered May 12, 2016 at 13:02

George Pant

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Comments

Wobbles · Accepted Answer · 2016-05-12 12:58:11Z

0

You are trying to get a post variable for a field named tagz, but you do not have a field named tagz (at least not in the code you have provided).

Consider changing the HTML to this:

<select name="tagz" multiple="multiple" class="select tagz" required>

answered May 12, 2016 at 12:58

Wobbles

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