How to generate case insensitive string with random module

Question

I need to generate random 32-digit number along with 15-character string to get something like 09826843-5112-8345-7619-372151470268 and qcRtAhieRabnpUaQ. I use following code to generate number:

import random

"-".join(['%08d' % random.randrange(0, 10e7), 
          '%04d' % random.randrange(0, 10e3), 
          '%04d' % random.randrange(0, 10e3), 
          '%04d' % random.randrange(0, 10e3), 
          '%012d' % random.randrange(0, 10e11)])

Is there a similar way to create case insensitive 15-char string with just random module?

Sergey Gornostaev · Accepted Answer · 2016-05-20 07:27:58Z

3

import random
import string
''.join(random.sample(string.ascii_letters, 15))

import uuid
str(uuid.uuid4())

answered May 20, 2016 at 7:27

Sergey Gornostaev

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1 Comment

Amit Tripathi Over a year ago

Note docs.python.org/2/library/random.html#random.sample is without replacement. So, the first approach can't produce a string with two or more similar digits.

lightalchemist · Accepted Answer · 2016-05-20 07:49:50Z

import numpy as np
import random
import string


def random_string(num_chars, symbols):    
    return "".join(random.choice(symbols)
                   for _ in range(num_chars))


def random_string2(num_chars, symbols, replace=True):
    """Random string with replacement option"""
    symbols = np.asarray(list(symbols))
    return "".join(np.random.choice(symbols, num_chars, replace))

def main():
    print(random_string(15, string.ascii_letters))
    print(random_string2(15, string.ascii_letters, False))
    print(random_string2(15, string.ascii_letters, True))


if __name__ == "__main__":
    main()

Note that elements in string need not be unique (which I presume to be the case since "qcRtAhieRabnpUaQ" has 2 'a').

If you want the elements to be unique, then @Sergey Gornostaev's solution is probably the most elegant, but that will impose the number of unique elements in ascii_letters as the longest string you can generate.

wildwilhelm · Accepted Answer · 2016-05-20 08:04:45Z

1

import random

rand_cap = [chr(random.randint(65, 90)) for i in range(7)]
rand_small = [chr(random.randint(97, 122)) for i in range(7)]
rand_chars_list = rand_cap + rand_small

random.shuffle(rand_chars_list)

rand_chars = ''.join(rand_chars_list)

edited May 20, 2016 at 8:04

wildwilhelm

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answered May 20, 2016 at 7:27

Amit Tripathi

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4 Comments

wildwilhelm Over a year ago

This solution is doing random draws without replacement (shuffle), where you should be doing with replacement (sample). If you check the question, you'll see that there's two as in the example random string. Your method can't produce this.

Amit Tripathi Over a year ago

@wildwilhelm I juts produced ''uEladCFBEatFgA'' (2 as)with above method. What do you mean by "two as in the example random string. Your method can't produce this"?

Andersson Over a year ago

This seem to solve the issue, just do edit: you use rand_cap and rand_char_cap in your code. I suppose these are the same variable.

wildwilhelm Over a year ago

Another correction to my comment: sample is drawing without replacement as well. choice is the right way to do drawing with replacement, as in @lightalchemist's answer.

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